Answer:
Change in momentum, 
Explanation:
It is given that,
Mass of the basketball, m = 601 g = 0.601 kg
The basketball makes an angle of 29 degrees to the vertical, it hits the floor with a speed, v = 6 m/s
It bounces up with the same speed, again moving to the right at an angle of 29 degree to the vertical. We need to find the change in momentum. It is given by :
So, the change in momentum of the basketball is 6.3 kg-m/s. Hence, this is the required solution.
Answer:
heya answer option b
Explanation:
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Answer:
Explanation:
Change in length of spring = 2.13 m
Component of weight acting on spring = mg sinθ
so
mg sinθ = k x where k is spring constant and x is total stretch due to force on the spring.
Here x = 2.13
mg sin17 = k x 2.13
31 x 9.8 sin17 = k x 2.13
k = 41.7 N/m
b ) In case surface had friction , spring would have stretched by less distance .
It is so because , the work done by gravity in stretching down is stored as potential energy in spring . In case of dissipative force like friction , it also takes up some energy in the form of heat etc so spring stretches less.
Answer: Force = Mass X Acceleration
F = 5 x 2
F = 10 N
