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3 years ago

8

t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is pl

aced 5 cm from the muzzle?

1 answer:

DerKrebs [107]3 years ago

5 0

Answer:

10

Explanation:

15 cm minus 5 cm

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The energy a glass has as you are holding it still above a table is

Novosadov [1.4K]

Energy <span>due to position is potential energy</span>

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3 years ago

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How long will it take a car to speed up from 10m/s to 34m/s if it can accelerate 8m/s/s in the direction it is moving?

diamong [38]

Answer:

3 s

Explanation:

velocity=initial velocity +a*t

34=10 + 8t

24=8t

t=3 s

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3 years ago

Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Natali5045456 [20]

Answer:

Acceleration, $a=3.6\times 10^{16}\ m/s^2$

Explanation:

It is given that, two isolated protons are separated by 2 nm. The force due to charged particles is given by :

$F_e=\dfrac{kq^2}{d^2}$

Force due to mass of proton, $F_g=ma$

$ma=\dfrac{kq^2}{d^2}$

$a=\dfrac{kq^2}{md^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.6\times 10^{-27}\times (2\times 10^{-9})^2}$

$a=3.6\times 10^{16}\ m/s^2$

So, the acceleration of two isolated protons is $3.6\times 10^{16}\ m/s^2$ . Hence, this is the required solution.

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2 years ago

A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.

vesna_86 [32]

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

$E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J$

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3 years ago

Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long

NNADVOKAT [17]

Answer:

a) 578.0 cm²

b) 25.18 km

Explanation:

We're given the density and mass, so first calculate the volume.

D = M / V

V = M / D

V = (6.740 g) / (19.32 g/cm³)

V = 0.3489 cm³

a) The volume of any uniform flat shape (prism) is the area of the base times the thickness.

V = Ah

A = V / h

A = (0.3489 cm³) / (6.036×10⁻⁴ cm)

A = 578.0 cm²

b) The volume of a cylinder is pi times the square of the radius times the length.

V = πr²h

h = V / (πr²)

h = (0.3489 cm³) / (π (2.100×10⁻⁴ cm)²)

h = 2.518×10⁶ cm

h = 25.18 km

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2 years ago