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Troyanec [42]
3 years ago
5

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of

the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 6.3 s, what is the depth of the crater?
Physics
1 answer:
leva [86]3 years ago
3 0

Answer;

=32.15 meters

Explanation;

Use the formula  

s= ut+ 0.5 a (t)^2 to find out 's'  

where s= distance traveled  

u=initial velocity which is zero in this case  

t= time taken to travel 's' distance  

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )  

Therefore;

S = 0.5 * 1.62 * 6.3 * 6.3

    = 32.1489 meters

Thus; the crater is 32.15 meters deep.

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Answer:

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Time taken by the bus to travel is, t = 15 minutes

The velocity is given by the formula

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Substituting the values in the above equation

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Learn more about final velocity here: brainly.com/question/25905661

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