Answer:
The correct option is;
B) 179 g
Explanation:
The parameters given are;
Mass of H₂ that takes part in the reaction = 2.23 g
Molar mass of hydrogen gas, H₂ = 2.016 g
Number of moles, n, of hydrogen gas H₂ is given by the relation;
Chemical equation for the reaction;
H₂ + Br₂ → 2HBr
Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr
1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr
The molar mass, of HBr = 80.91 g/mol
The mass of HBr produced = Molar mass of HBr × Number of moles of HBr
The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams
Therefore, the correct option is B) 179 g.
Answer:
table C will be the correct answer
Answer: The final molarity of the diluted oxalic acid solution is 0.0032 M
Explanation:
Molarity: It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= moles of solute
Moles=
= volume of solution in ml
To calculate the final molarity of the diluted oxalic acid solution
where,
are the molarity and volume of concentrated oxalic acid solution.
are the molarity and volume of diluted oxalic acid solution.
We are given:
Putting values in above equation, we get:
Thus the final molarity of the diluted oxalic acid solution is 0.0032 M
3.25 kg in g = 3.25 * 1000 = 3250 g
Molar mass C₂H₆O₂ = 62.0 g/mol
Mass solvent = 7.75 kg
Number of moles:
n = mass solute / molar mass
n = 3250 / 62.0
n = 52.419 moles
Molality = moles of solute / kilograms of solvent
M = 52.419 / 7.75
M = 6.7637 mol/kg
hope this helps!
Answer:
If the temperature and volume ot a gas increases, the r.m.s. velocity of the molecules in the gas will be 2 times the original r.m.s. molecular velocity.
If T doubles while V is held constant, the new net internal energy of the gas will be 2 times the original internal energy of the gas.
Explanation:
Temperature and root mean square velocity are directly proportional to one anoth. If the temperature increases, root mean square velocity also increases and vice versa, while temperature is also directly proportional to the internal energy of the gas molecules, higher the temperature, higher will be the internal energy and lower the temperature so internal energy will be decreased.
