Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.
That can be mathematical computed from the expression:
Osmotic pressure=C×R×T
Where,
C= Concentration 
R=Gas constant
T=Temperature
Concentration=Number of moles of solute/Volume(L)
 =0.005*1000/100
 =0.05
R= 0.08206 atm L/mol K
T=25+273
=298
Osmotic pressure= 0.05×0.08206×298
 =1.2 atm
 
        
             
        
        
        
The half life for C14 is 5730 years.
We assume that Carbon 14/ Carbon 12 ratio was steady for living organisms over time, the problem is actually telling us that

 = 0.0725 = 

ˣ
Take the natural logarithm and In on both sides.
ln(0.725) = ln

ˣ
= - 0.3216 = xln (

 = -0.6931x.
So x = (-.3216) / (-0.6931) = 0.464
or
t/t₁/₂ = 0.464
So t = 0.464 x t₁/₂ = 0.464 * 5730 yrs = 2660 years.
 
        
        
        
Any substance that accept a proton by definition is considered to be BRONSTED LOWRY BASE.
Bronsted Lowry defined acid and base on the basis of donating or accepting protons. In the Bronsted Lowry classification of acid and base, an acid is defined as a substance which donate proton while a base is defined as a substance which accept proton.
        
                    
             
        
        
        
<h3>Further explanation</h3>
Basic oxides ⇒ metal(usually alkali/alkaline earth) +O₂
L + O₂ ⇒ L₂O
L + O₂ ⇒ LO
Dissolve in water becomes = basic solution
L₂O+H₂O⇒ 2LOH
LO + H₂O⇒ L(OH)₂
So the basic oxides : Na₂O and MgO
Na₂O + H₂O⇒NaOH
MgO +H₂O⇒Mg(OH)₂
The aqueous solution of CO₂(dissolve in water)
CO₂ + +H₂O⇒ H₂CO₃(carbonic acid)
 
        
        
        
Answer: here is your answer 
Explanation: You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.