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Dmitry [639]
3 years ago
9

Why are digestive enzymes in a cell enclosed in a membrane

Chemistry
1 answer:
erastova [34]3 years ago
7 0
The membrane<span> keeps the </span>digestive <span>materials from leaking out into the cytoplasm and destroying the </span>cell<span>.
</span><span>
</span>
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A 425.00-gram sample of a compound decomposes into 196.01 grams of carbon, 41.14 grams of hydrogen, 130.56 grams of oxygen, and
Alenkasestr [34]

The molecular formula is D. C_8H_20O_4Si.

<em>Step 1</em>.Calculate the <em>empirical formula </em>

a) Calculate the moles of each element

Moles of C= 196.01 g C × (1 mol C/12.01 g C) = 16.325 mol C  

Moles of H = 41.14 g H × (1 mol H/1.008 g H) = 40.813 mol H

Moles of O = 130.56 g O × (1 mol O/16.00 g O) = 8.1650 mol O

Moles of Si = 57.29 g Si × (1 mol Si/28.085 g Si) = 2.0399 mol Si

b) Calculate the molar ratio of each element

Divide each number by the smallest number of moles and round off to an integer

C:H:O:Si = 8.0027:20.008:4.0027:1 ≈ 8:20:4:1

c) Write the empirical formula

EF = C_8H_20O_4Si

<em>Step </em>2. Calculate the <em>molecular formula</em>

EF Mass = 208.33 u

MF mass = 208.329  u

MF = (EF)_n

n = MF Mass/EF Mass = 208.329 u/208.33 u = 1.0000 ≈ 1

MF = C_8H_20O_4Si

3 0
3 years ago
Which of these best describes a flight that is approaching the speed of sound
liberstina [14]
More drag is created because the air molecules are not moving out of the way of the airplane      
8 0
3 years ago
Read 2 more answers
How much silver is produced is 15.00 grams of cu is added to the solution of excess silver nitrate?
il63 [147K]
First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
6 0
3 years ago
Metamorphic rocks with a non-foliated texture show metamorphic change that involves ____.
matrenka [14]

Answer:

b.  growth in the size of the mineral grains

Explanation:

Non-foliated texture shown by a metamorphic change is depicted by growth in the size of the mineral grains.

  • Examples of non-foliated metamorphic rocks are quartzite and marble.
  • In these metamorphic rocks, mineral grains are not aligned with their long axis.
  • Non-foliated texture occurs under high temperature and low pressure conditions.
  • As minerals are able to grow, the size can be used to show a metamorphic change.
8 0
3 years ago
When phenolphthalein indicator is added to a colorless solution with a pH of 10, a student observes and concludes that the teste
madam [21]

Answer:

3.  turns pink and is basic

Explanation:

Phenolphthalein is a pH indicator that remains colorless in acidic solutions, but in basic solutions it turns pink at a pH equal to 10.

Phenolphthalein is a weak acid that loses H+ cations in solution. The phenolphthalein molecule is colorless, while the phenolphthalein-derived anion is pink. When a base is added, phenolphthalein loses H+, forming the anion and causing it to turn pink. The color change cannot be explained only on the basis of deprotonation, a structural change occurs with the appearance of a ketoenolic tautomerism.

4 0
2 years ago
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