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nika2105 [10]
2 years ago
15

Which of the following is the correct molecule for dinitrogen trisulfide?

Chemistry
2 answers:
BabaBlast [244]2 years ago
8 0

Answer:

Option A. N2S3

Explanation:

The easiest way to know this, is to look into the molecules. Let's discart the given options before we choose the correct one.

For beggining we need a moleculae that have 2 atoms of nitrogen and 3 of sulfur.

Option B:

This cannot be the, because for starter, we see the number 2 before the N, this means that is a coefficient and not an atom. An atom of any element is always as subscript. In this molecule, only the number 3 is supposed to be subscripted.

Option C.

We can see that it has only 2 atoms of sulfur, and at the beggining is stated that we need 3, so we can discart rapidly this option.

Option D:

Again, because of the numbers there, we can be confused and think is the correct option, but remember what it was stated before. The atoms should be as subscrip. This is not the case, only the atoms of Nitrogen are subscripted but the number 3 there is put as coefficient, or even can be part of the nitrogen, so instead of being two atoms, we have 23 atoms of Nitrogen.

Therefore, the correct option is A, cause we can see the number 2 and 3 as subscript.

Setler79 [48]2 years ago
4 0

Answer:

A. N2S3

yep u r right

Explanation:

Dinitrogen Trisulfide N2S3 Molecular Weight -- EndMemo.

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Position (m)
Alex777 [14]

Option C. The object is returning to the start at a constant speed.

<h3>Data points of the Position vs Time graph</h3>

The following data points will be used to determine the motion of the object.

<u>Position               Time</u>

12                          4

10                          6

2                            8

0                           10

From the data above, the position of the object is decreasing towards zero or start point.

Thus, the object is returning to the start at a constant speed.

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8 0
1 year ago
What is oxidation number of S in H2SO5??​
mote1985 [20]

★ « <em><u>what is oxidation number of S in H2SO5??</u></em><em><u> </u></em><em><u>»</u></em><em><u> </u></em><em><u>★</u></em>

  • <em><u>it's </u></em><em><u> </u></em><em><u>6</u></em><em><u>!</u></em><em><u>!</u></em>

Explanation:

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3 0
2 years ago
Read 2 more answers
A buffer solution is composed of 1.00 mol of acid and 2.25 mol of the conjugate base. If the p K a of the acid is 4.90 , what is
Gemiola [76]

<u>Answer:</u> The pH of the buffer is 5.25

<u>Explanation:</u>

Let the volume of buffer solution be V

We know that:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})

We are given:

pK_a = negative logarithm of acid dissociation constant of weak acid = 4.90

[\text{conjugate base}]=\frac{2.25}{V}

[acid]=\frac{1.00}{V}

pH = ?

Putting values in above equation, we get:

pH=4.90+\log(\frac{2.25/V}{1.00/V})\\\\pH=5.25

Hence, the pH of the buffer is 5.25

4 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
3 years ago
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