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nika2105 [10]
2 years ago
15

Which of the following is the correct molecule for dinitrogen trisulfide?

Chemistry
2 answers:
BabaBlast [244]2 years ago
8 0

Answer:

Option A. N2S3

Explanation:

The easiest way to know this, is to look into the molecules. Let's discart the given options before we choose the correct one.

For beggining we need a moleculae that have 2 atoms of nitrogen and 3 of sulfur.

Option B:

This cannot be the, because for starter, we see the number 2 before the N, this means that is a coefficient and not an atom. An atom of any element is always as subscript. In this molecule, only the number 3 is supposed to be subscripted.

Option C.

We can see that it has only 2 atoms of sulfur, and at the beggining is stated that we need 3, so we can discart rapidly this option.

Option D:

Again, because of the numbers there, we can be confused and think is the correct option, but remember what it was stated before. The atoms should be as subscrip. This is not the case, only the atoms of Nitrogen are subscripted but the number 3 there is put as coefficient, or even can be part of the nitrogen, so instead of being two atoms, we have 23 atoms of Nitrogen.

Therefore, the correct option is A, cause we can see the number 2 and 3 as subscript.

Setler79 [48]2 years ago
4 0

Answer:

A. N2S3

yep u r right

Explanation:

Dinitrogen Trisulfide N2S3 Molecular Weight -- EndMemo.

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The radioisotope phosphorus-32 is used in tracers for measuring phosphorus uptake by plants. The half-life of phosphorus-32 is 1
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Answer:

54 days

Explanation:

We have to use the formula;

0.693/t1/2 =2.303/t log Ao/A

Where;

t1/2= half-life of phosphorus-32= 14.3 days

t= time taken for the activity to fall to 7.34% of its original value

Ao=initial activity of phosphorus-32

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Note that;

A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)

Substituting values;

0.693/14.3 = 2.303/t log Ao/0.0734Ao

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0.693/14.3 = 2.6/t

0.048=2.6/t

t= 2.6/0.048

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3 0
3 years ago
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QUESTION 2
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Answer:

you can see the answer at the pic

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