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1 year ago

Given substances f2, kr, cl2 and hbr rank them with respect to the highest boiling point?

Chemistry

1 answer:

Inessa05 [86]1 year ago

3 0

The Hbr has highest boiling point followed by Kr , $Cl_{2}$ and $F_{2}$ .

The Hbr has highest boiling point due to presence of intermolecular H-bonding that is hydrogen bonding.

The electronegativity of bromine is greater than hydrogen atom. The electronegativity difference hydrogen atom and bromine atom is high. So, due to this a positive dipole is generated at hydrogen atom and partial negative charge, these partial charge is called dipole. In a HBr molecule one H-atom attracted by Br-atom of another atom by force of attraction and this partial force of attraction is called H-bonding.

Other all given molecules are arrange according to its molecular mass because boiling points is directly proportional to the molecular mass of molecule.

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Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

3 0

2 years ago

What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?

lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P) $\frac{3.8}{31} =0.123$

Hydrogen (H) $\frac{0.371}{1} =0.371$

Then you divide by the lowest number:

$\frac{0.123}{0.123} = 1$ for phosphorus

$\frac{0.371}{0.123} = 3$ for hydrogen

So the empirical formula will be:

$PH_{3}$

6 0

3 years ago

How man grams of cl2 are consumed to produce 12.0 g of KCl

Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0

3 years ago

How many grams are in 4 moles of H2O?

ivanzaharov [21]

Answer:

There are 72grams in 4 moles of H20

8 0

2 years ago

The reaction is found to be first order in IO3−, first order in SO32−, and first order in H+. If [IO3−]=x, [SO32−]=y, and [H+]=z

ollegr [7]

Answer:

rate = kxyz

Explanation:

It is worth knowing that the rate low can only be determined by experimentation only not by just balancing equations. So here we are told that all the reactants x , y and z are all first order. This is important because we use this as exponents. That is why the exponents of all the reactants will be 1.

rate = kxyz

7 0

2 years ago