3 years ago

Find the mass in 6.2 miles of lithium bromide, show work

Chemistry

1 answer:

Delicious77 [7]3 years ago

7 0

Answer:

if you meant moles this is the answer 1

mol of lithium bromide has a mass of

86.85g⋅mol−1. You have 2.6 moles

Explanation: mass = 86.85g⋅ mol−1× 2.6 mol

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3 years ago

Explain how changing the concentration The enthalpy change for the reaction, 3CO (g) 2Fe2O3 (s) Imported Asset Fe(s) 3CO2 (g), c

ycow [4]

<u>Answer:</u> For the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

$3CO(g)+2Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]$