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zheka24 [161]
2 years ago
8

How many grams of sodium hydroxide (NaOH) do you need to get rid of 3000 grams of CO2? Don't worry about sig figs for this quest

ion.
Chemistry
1 answer:
Slav-nsk [51]2 years ago
8 0

Answer:

It would require 80 g of NaOH .

Explanation:

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In an electron dot diagram of propane (C3H8), how many double bonds are present?
NeX [460]

Answer:- none

Explanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne.

-ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons.

The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in C_3H_8 .

This is also clear from the below lewis dot structure of the compound.


4 0
3 years ago
Read 2 more answers
PLEASE HELP!?Consumers must eat other organisms for energy. Which organisms are consumers in this food chain?
Vitek1552 [10]

Answer:

Consumers must consume other organisms to get the food that they need and are known as Heterotrophs as they cannot make their own glucose. These consumers eat producers (plants). Herbivores are considered as first order consumers. These consumers eat consumers and producers (animals and plants).

4 0
2 years ago
N2-3H2 → 2NH3
aniked [119]

Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

\frac{2 mol N_{2} }{1} * \frac{3 mol H_{2}  }{ 1 mol N_{2} } = 6 mol H2

8 0
3 years ago
You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
Help please
Mars2501 [29]

Answer:

electron cloud charge of manganese=-5

Explanation:

atomic number=number of elecron +neutron number

DATA

Neutron NO.=30

atomic NO.=25

e=?

A=e+n

25=e+30

e=25-30

e= -5

6 0
2 years ago
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