Answer:
The final temperature of the mixture is 22.3°C
Explanation:
Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:
Heat lost = Heat gained
Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change =<em> Tfinal - Tinitial</em>.
Let the final temperature be T
Heat lost = 120 × c × (T - 80)
Heat gained = 3000 × c × ( T - 20)
Equating the heat lost and heat gained
120 × c × -(T - 80) = 3000 × c × (T - 20)
9600 - 120T = 3000T - 60000
60000 + 9600 = 3000T + 120T
69600 = 3120T
T = 69600/3120
T = 22.3°C
Therefore, the final temperature of the mixture is 22.3°C
Start studying Pressure - Volume Relationships in Gases (Boyle's Law). Learn vocabulary, terms ...Select<span> all that apply. V2 = k/P2 V2 = P1V1/P2 ... What </span>two variables<span> are </span>held constant when testing Boyle's Law in a manometer<span>? Temperature hope this helps
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Answer:
The correct answer is a coenzyme cosubstrate is loosely bound to an enzyme and dissociates in an altered form as the part of the catalytic cycle.Its original form is regenerated not by the cycle but by other enzyme.
Explanation:
The prosthetic group of the enzyme pyruvate dehydrogenase is
2 TPP or Thymine pyrophosphate.
3 Lipomide.
Answer:
0.83 g
Explanation:
Step 1: Write the balanced equation
Fe + CuSO₄ ⇒ Cu + FeSO₄
Step 2: Calculate the moles corresponding to 0.75 g of Fe
The molar mass of Fe is 55.85 g/mol.
Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe
The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.
Step 4: Calculate the mass corresponding to 0.013 moles of Cu
The molar mass of Cu is 63.55 g/mol.
