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horrorfan [7]
3 years ago
5

sasha needs an average of 30 points to move to the next level in her competion . her scores in the first three events are 28, 35

, and 30. what is the lowest score she can score?
Mathematics
1 answer:
salantis [7]3 years ago
3 0
Sarah will need 27pts her lowest score
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What is 9x-5x ????i need help
Dima020 [189]

Hi there!

Answer:

<u><em>=4x</em></u>

Step-by-step explanation:

Distributive property: ⇒ a(b+c)=ab+ac

You had to add similar elements.

9x-5x=4x

5x+4x=9x

9x-4x=5x

final answer: =4x

Hope this helps!

-Charlie

Have a great day!

4 0
3 years ago
Suppose that a loan of $8000 is given at an interest rate of 16% compounded each year.
mash [69]

Answer:

9280

Step-by-step explanation:

8000 x .16 + 8000

6 0
3 years ago
What is the slope-intercept form of the line passing through the point (2, 1) and having a slope of 4?
patriot [66]

Answer:

1=4(2)-7

Step-by-step explanation:

y=mx+b

b=where it crosses the y-axis

m=slope

1=4(2)-7

6 0
3 years ago
A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9​, and the sample stand
yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

H_0:\mu=100 and H_1:\mu \:>\:100 (claim)

<u>Step 2</u>: Calculate the test value.

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }

\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value  is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for \alpha=0.05 and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0
4 years ago
A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden
solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P  = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99%   = 1 - 0.99

α  = 0.01

and  \frac{\alpha}{2} = \frac{0.01}{2}

\frac{\alpha}{2}  = 0.005

so Z is here

Z_(\frac{\alpha}{2}) = 2.576

so

sample size will be

Sample size n =  (\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0
3 years ago
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