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algol13
3 years ago
7

Adenosine triphosphate, or ATP, is primarily used as _______ in living organisms.

Chemistry
2 answers:
Stolb23 [73]3 years ago
5 0
It is primarily used as a way to supply  energy to other cells
Llana [10]3 years ago
5 0

Answer:

a source of energy

Explanation:

Adenosine triphosphate, or ATP, is primarily used as a source of energy in living organisms.

You might be interested in
Some of the most dangerous conditions occur when temperatures are hovering around _______ degrees fahrenheit, or freezing, when
Olin [163]

Answer:

32 ° F

Explanation:

Freezing temp for water is 32 degrees at 1 atm

3 0
2 years ago
A sample of nitrogen gas is stored in a 592.2 mL flask at 108 kPa and 10.0°C. The gas is transferred to a 750.0 mL flask at 28.9
vfiekz [6]
According to Gases law, we know, 
PV/T = Constant

So, P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9

Substitute their values, 

108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa

In short, Your Final Answer would be: 90.97 kPa

Hope this helps!
8 0
4 years ago
Can someone answer all 3 questions plz?
nordsb [41]

Question one should be obvious..

Mass can't be created not destroyed no matter what, so even in a chemical reaction, the answer will remain. The first answer is correct.

Question two

No, because even when water is broken down, there should only be one molecule of oxygen. The fact there is two means it's incorrect.

Question three

Yes. The equation is perfectly balanced on both sides, so it's safe to say the value of mass remains constant.

3 0
3 years ago
An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola
liq [111]

<u>Answer:</u> The molality of NaC_2H_3O_2 solution is 0.782 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}} .....(1)

Given values:

Moles of NaC_2H_3O_2 = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m

Hence, the molality of NaC_2H_3O_2 solution is 0.782 m

8 0
3 years ago
5. What could you do to convert from meters to centimeters? *
maria [59]

C.

centi- is essentially 10^2 of one meter.

If you had 100m, multiplying 100 by 10^2 (or 100) would give you 10000 cm.

7 0
3 years ago
Read 2 more answers
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