The correct answer would be option 3. I order for a single displacement to occur there must be a single element and one compound. From then, the single element will then swap places with one of the elements in the compound (or in this case single circle and combined circles). Hope this helped!
Answer:
Explanation:
You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.
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<u>1. Number of moles of H</u><u>₂</u>
- number of moles = mass in grams / molar mass
- molar mass of H₂ = 2.016g/mol
- number of moles = 6.00grams / 2.016g/mol = 2.97619mol
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<u>2. Number of moles of NH</u><u>₃</u>
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i) Chemical equation:
ii) Mole ratio:
iii) Proportion:
- x mol NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂
<u>3. Volume of NH₃</u>
- V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm
Answer:
Okay ask away. . . You haven't asked anything that we would be able to answer
Answer:
iron = 15000 kg 95% sulfuric acid = 27646.32 kg
Explanation:
The molar volume to a gas is 22.4 L, which means that a mole of a given gas at 0°C and 1 atm will have a volume os 22.4 L.
1 m3 - 1000 L
4870 m3 - x
x = 4870 * 1000 = 4.87 *10^6 L
1 mole - 22.4 L
y mole - 4.87 * 10^6 L
y = 
= 2,17 *10^5 moles (if 100% of the H2 is used)
as 20% of it is lost, we need to know how much more we need to use.
80% - 2.17 * 10^5 moles
100% - z
z = 
= 2,68*10^5 moles
so we would need 2.68*10^5 moles of iron and sulfuric acid.
1 mole of iron - 56 *10^-3 kg
2.68*10^5 moles - t
t= 2.68*56 *10^2 = 15000 kg
1 mole of sulfuric acid - 98 * 10^-3 kg
2.68*10^5 - u
u = 2.68*98 *10^2 = 26264 kg (if 100%)
95% - 26264 kg
100% - v
v = 
= 27646.32 kg
The answer is b because the wind exerts a force on the kite
