Answer:
Acceleration of the car is .
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :
So, the acceleration of the car as it speeds up is . Hence, this is the required solution.
Explanation:
It is given that,
= -40 mi/h, = -40 mi/h
The negative sign indicates that x and y are decreasing.
We have to find . Equation for the given variables according to the Pythagoras theorem is as follows.
Now, we will differentiate each side w.r.t 't' as follows.
or,
So, when x = 4 mi, and y = 3 mi then z = 5 mi.
As,
=
=
= 52
Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.
Answer:
El esfuerzo cortante, de corte, de cizalla o de cortadura es el esfuerzo interno o resultante de las tensiones paralelas a la sección transversal de un prisma mecánico como por ejemplo una viga o un pilar. Se designa variadamente como T, V o Q.
Este tipo de solicitación formado por tensiones paralelas está directamente asociado a la tensión cortante. Para una pieza prismática se relaciona con la tensión cortante mediante la relación:
(1){\displaystyle Q_{y}=\int _{\Sigma }\tau _{xy}\ dydz,\qquad Q_{z}=\int _{\Sigma }\tau _{xz}\ dydz,\qquad Q={\sqrt {Q_{y}^{2}+Q_{z}^{2}}}}
Para una viga recta para la que sea válida la teoría de Euler-Bernoulli se tiene la siguiente relación entre las componentes del esfuerzo cortante y el momento flector:
Yes light travels at 3.00
Answer:
<h3>The answer is 0.67 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>0.67 m/s²</h3>
Hope this helps you