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Verdich [7]
3 years ago
5

What did Thomson's and Rutherford's experiments have in common?

Physics
2 answers:
Zepler [3.9K]3 years ago
6 0

Answer:

the answer is A

Explanation:

sdas [7]3 years ago
4 0
<span>They both used charged particles in their experiments.</span>
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The variables for Part II of this experiment include the force applied to the car and the acceleration of the car. Use the drop-
gregori [183]

Answer:

Independent variable: Force applied to the car

Dependent variable: The acceleration of the car

Explanation:

A scientific experiment involves three variables which are classified mainly as independent, dependent and constant variables.

The independent variable is the variable which can be changed or changes itself like weather, natural conditions and in a given question, the applied force on the car is considered.

The dependent variable is the variable which depends on the independent variable that is the force applied on the car. Therefore, the acceleration of the car can be considered as a dependent variable as it changes according to the applied force.

8 0
3 years ago
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If the 50-kg box is lifted 0.4 m with an 8 m/s2 acceleration, what would be the work done?
grigory [225]

Explanation:

work done=force ×distance

force=Mass ×accelleration

work done=50×8×0.4

=160J

please like and Mark as brainliest

3 0
3 years ago
A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr
fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}

The values are

\displaystyle y_o=15\ m

\displaystyle v_o=14\ m/s

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

\displaystyle y=0

\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0

Multiplying by 2

\displaystyle 2y_o+2v_ot-gt^2=0

Clearing the coefficient of t^2

\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0

Plugging in the given values, we reach to a second-degree equation

\displaystyle t^2-2.857t-3.061=0

The equation has two roots, but we only keep the positive root

\displaystyle \boxed {t=3.69\ s}

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

\displaystyle Y_r=15+V_r.t

\displaystyle Y_r=15+14\times3.69

\displaystyle \boxed{Y_r=66.62\ m}

3 0
3 years ago
Provide examples of Thermodynamics.
vampirchik [111]
Thermodynamics is the branch of physical science which deals with the relationship between heat and other forms of energy like chemical energy, mechanical or electrical. Here are examples of thermodynamics that are commonly seen in everyday living: When you accidentally wrecked or bumped your car, you came out alive and just slightly hurt, because it was the car that that absorbed the energy of the impact. Another example is that, during cooking. When you are cooking, the heat is being transferred to the pan and then to the food that you are cooking.
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4 years ago
What colors of visible light do green plant leaves absorb the most?
riadik2000 [5.3K]
B.  Red and Blue is the correct answer
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3 years ago
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