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Anettt [7]
3 years ago
15

Help pls it’s urgent giving brainiest!!

Physics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

2nd no. positive.... 3rd no. negitive......

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As more resistors are added in series across a constant voltage source, the power supplied by the source: A) does not change. B)
Anon25 [30]

As series resistors are added, the resistance is added directly so the total resistance will be equal to

R_T = R_1+R_2+R_3... R_{\infty}

Since the power is determined as

P = \frac{V^2}{R}

We have there that

P \propto \frac{1}{R}

The power is inversely proportional to the increase in resistance, so it will tend to decrease as more resistors are added in series.

The correct answer is: C.

4 0
3 years ago
What is the address of the earth?
sesenic [268]
Earth is a planet located in the milky way galaxy.<span />
3 0
3 years ago
A 817 kg car has four 8.91 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to rot
KATRIN_1 [288]

Answer:

0.0107

Explanation:

We know that

The rotational kinetic energy due to four wheel is

1/2ဃ²I x 4

So

1/4mR²(v/R)² = mv²

But kinetic energy along straight path of the car is 1/2mv²

=> 1/2( 817)v ²

Kc= 408.5v²

So The fraction of total kinetic energy that is due to rotation of the wheel about their axis

Is Kw/Kw+Kc

and Kw = 1/2* 8.91v²= 4.45v²

So 4.45v²/ 4.45v²+ 408.5v²

= 0.0107 as fraction of total kinetic energy

8 0
3 years ago
An object is moving but we don't know its mass or velocity. A force of 20 newtons to the right
jok3333 [9.3K]

The impulse is (force) x (time) = (20 N) x (20 sec) = 400 N-sec

When we grind through the units, we find that the [newton-second]
is exactly the same as the [kilogram-meter/sec] unit-wise, and once
we know that, it doesn't surprise us to learn that impulse is equivalent
to a change in momentum (mass x speed ... also kg-m/s).

So this impulse exerted on the moving object adds 400 kg-m/s of
linear momentum to its motion, directed to the right.  That may or
may not be the total change in its momentum during that 20-sec,
because our 20-N may not be the only force acting on it.


8 0
3 years ago
A 70.0-kg skier is sliding at 4 m/s when they slide down a 2m high hill. At the bottom of the hill they run into a large 2800 N/
Katarina [22]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • mass of skier, m=70\ kg
  • initial velocity of skier, u=4\ m.s^{-1}
  • height of the hill, h=2\ m
  • spring constant, k=2800\ N.m^{-1}

<u>final velocity of skier before coming in contact of spring:</u>

Using eq. of motion:

v^2=u^2+gh

v^2=4^2+9.8\times 2

v=5.9666\ m.s^{-1}

<u>Now the time taken by the skier to reach down:</u>

v=u+gt

5.9666=4+9.8\ t

t=0.2007\ s

<u>Now we calculate force using Newton's second law:</u>

F=\frac{dp}{dt}

F=\frac{m(v-u)}{t}

F=\frac{70\times(5.9666-4)}{0.2007}

F\approx686\ N

<u>∴Compression in spring before the skier momentarily comes to rest:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{686}{2800}

\Delta x=0.245\ m

\Delta x=245\ mm

4 0
3 years ago
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