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3 years ago

Help pls it’s urgent giving brainiest!!

Physics

1 answer:

Lorico [155]3 years ago

3 0

Answer:

2nd no. positive.... 3rd no. negitive......

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The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of

snow_tiger [21]

Answer:

Explanation:

Given

height of grand canyon is $h=1800\ m$

Rock is dropped i.e. initial velocity is zero

$u=0$

Using Equation of motion

$h=ut+\frac{1}{2}at^2$

h=height

u=initial velocity

a=acceleration

t=time

here a=acceleration due to gravity

$1800=0+\frac{1}{2}\times 9.8\times t^2$

$t^2=\frac{2\times 1800}{9.8}$

$t=19.166\ s$

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3 years ago

Hans Eysenck makes a connection between __________ and __________in explaining personality development. A. genetic factors . . .

tekilochka [14]

The answer is A, genetic factors...conditioning. I just took the test. Good luck!!

6 0

4 years ago

Read 2 more answers

A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?

Vesna [10]

6.3 That Would be the I answer I think but Check on Google For the formula

6 0

3 years ago

A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17

Korolek [52]

Given:

Mass of cart: 15kg

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

So, the solution would be like this for this specific problem:

1) W(by applied force) = F(applied) x s x cosθ 
=>W(a) = 12 x 14 x cos17* = 160.66 J 

2) By F(net) = F(applied) - F(friction) 
=>As v = constant => a = 0 => F(net) = 0
=>F(applied) = F(friction)
=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s
=>W(f) = -12 x 14 x cos17* = -160.56 J 

3) 0, as the displacement is perpendicular to Force 

4) 0, as the displacement is perpendicular to Force

To add, the force that is applied to an object by a person or another object is called the applied force.

8 0

3 years ago

Two lightbulbs have powers P1 and P2 when separately connected across an ideal battery with potential difference ΔV. The bulbs a

jarptica [38.1K]

Answer:

$P'=\dfrac{P_1P_2}{P_1+P_2}$

Explanation:

Lets take

Resistance of bulb 1 =R₁

Resistance of bulb 2 =R₂

As we know that power P

P= ΔV²/R

Given that voltage difference is same for both bulbs

P₁R₁= ΔV² --------1

P₂R₂= ΔV² -----------2

When these resistance are connected in series then equivalent resistance R

R=R₁+ R₂

The new power P'

P'=ΔV²/R

P'R=ΔV² ------3

From equation 1 ,2 and 3

P'(R₁+ R₂) = ΔV²

$P'\left(\dfrac{\Delta V^2}{P_1}+\dfrac{\Delta V^2}{P_2}\right)=\Delta V^2$

$P'=\dfrac{P_1P_2}{P_1+P_2}$

6 0

4 years ago