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2 years ago

Help pls it’s urgent giving brainiest!!

Physics

1 answer:

Lorico [155]2 years ago

3 0

Answer:

2nd no. positive.... 3rd no. negitive......

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The velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration

Veseljchak [2.6K]

Answer:

acceleration = v-u/ t

= 15-10/5

= 5/5

= 1 m/s2

Explanation:

hope this helped you.

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2 years ago

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If three devices are plugged into one port on a switch and two devices are plugged into a different port, how many collision dom

Neporo4naja [7]

Collision domain is a portion in the network where there is a possibility of formation of packets. This occurs when two or more devices are able to send a packet to a single switch or port on the network that is shared, on the same time. It was noted that this collision domain reduces the efficiency of the network.

For this item, the first packet is the whole switch with the three devices. Next one would be first of the three devices that is connected to the other port. Similarly, the third one would be the second of the three devices that is also connected to the switch. Therefore, the answer is 3.

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3 years ago

Two football players are pushing a 60 kg blocking sled across the field at a constant speed of 2.0 m/s. The coefficient of kinet

MArishka [77]

Answer:

The sled slides d=0.155 meters before rest.

Explanation:

m= 60 kg

V= 2 m/s

μ= 0.3

g= 9.8 m/s²

W= m * g

W= 588 N

Fr= μ* W

Fr= 176.4 N

∑F = m * a

a= (W+Fr)/m

a= 12.74m/s²

t= V/a

t= 0.156 s

d= V*t - a*t²/2

d= 0.155 m

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3 years ago

Why are atoms arranged in periods ...???

Sati [7]

<span>A horizontal row in the periodic table, which signifies the total number of electron shells in an element's atom. A vertical column in the periodic table, which signifies the number of valence shell electrons in an element's atom.</span>

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3 years ago

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A 16 kg science book is dropped of a 120 meter high cliff. Assuming a closed system:

Lapatulllka [165]

Answer:

Explanation:

The mass of that science book...wow. In pounds that would be 35.2! Yikes!

Anyway, we need final velocity here, and the mass of the book has nothing to do with how fast it falls. Everything is pulled by the same gravity. A feather falls at 9.8 m/s/s and so does an elephant. Mass is useless information. The equation we will use is

$v^2=v_0^2+2a$ Δx where

v is the final velocity, our unknown,

v₀ is the initial velocity which is 0 since someone had to be holding the book before dropping it,

a is the pull of gravity which is always -9.8 m/s/s, and

Δx = -120 which is the displacement (it's negative because the book falls below the point from which it was dropped). Filling in:

$v^2=0^2+2(-9.8)(-120)$ so

$v=\sqrt{2(-9.8)(-120)}$ and

v = 48 m/s

As far as how far above the bottom of the cliff the object is when it is moving at 12 m/s we will use the same equation, but the velocity will be 12:

$12^2=0^2+2(-9.8)$ Δx and

144 = -19.6Δx so

Δx = -7.3 m. That's how far from the top of the cliff it is. We subtract then t find out how far it is from the bottom:

120 - 7.3 = 112.7 m off the ground.

6 0

2 years ago