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AVprozaik [17]
3 years ago
7

Which of the following items involve a wedge?

Physics
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0
B because under the blade it curves
Fynjy0 [20]3 years ago
6 0
I did some research and the answers are A. a chisel B. an axe and C. a knife
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A single-phase transformer has a turns ratio of 20,000/5,000. If a DC voltage of 50 V is applied to the primary winding, what wi
Kipish [7]

Sneaky question.

The secondary voltage will be zero.

Secondary voltage is the result of CHANGES in the primary voltage. That means the primary is energized with AC. The transformer in this question is energized with DC, which doesn't change. So there is no secondary voltage, this transformer doesn't work, and what you get out of it is: Smoke !

6 0
3 years ago
Plz help a smol bean out (no links btw)
Marina86 [1]
Hey! If this is on big ideas get a app called “Slader” It has answers to all math problems just like up the book you use > save it > type in the section you are doing > and look for the problems you are doing.
8 0
3 years ago
What is a synonym &amp; an antonym for property ?<br> What is a synonym of physical change ?
tigry1 [53]

Answer:

A synonym for property is a quality or a characteristic. An antonym is non-physical. A synonym of physical change is a change in state or activity. Phase transition or Natural action.

8 0
3 years ago
¿Qué distancia recorrió un avión que viajaba a 750 km/h después de 2 h y media de vuelo?
arsen [322]

Answer:

mehhvbhhhhhhhehshrbeheherhhehehthsjrjjrhrn

Explanation:

bdbsbdbi

7 0
3 years ago
A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an
Mademuasel [1]

Answer:

The angular acceleration is 0.209\ rad/s^2

Explanation:

Given that,

Angular velocity, \omega_{i} = 30.0\ rpm

Angular velocity, \omega_{f} = 50.0\ rpm

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

\alpha=\dfrac{\Delta \omega}{\Delta t}

\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}

\alpha=\dfrac{50.0-30.0}{10.0}

Now, we change the angular velocity in rad/s.

\omega=20\times\dfrac{2\pi}{60}

\omega=2.09\ rad/s

\alpha=\dfrac{2.09}{10.0}

\alpha=0.209\ rad/s^2

Hence, The angular acceleration is 0.209\ rad/s^2

5 0
3 years ago
Read 2 more answers
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