Ask question

Ask question

All categories

3 years ago

15

HELP PLEASE!! A musician is playing an instrument some distance away from the crowd. If the air temperature is 15 degrees Celsiu

s what is the speed of sound in this medium?

1 answer:

ycow [4]3 years ago

8 0

Answer:

weesdshrhrjjrjtjthht

You might be interested in

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the m

Paraphin [41]

Answer:

I2>I1

Explanation:

This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:

$I_2=I_{1}+Md^2$

where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.

It is clear that I2 is greater than I1 by the contribution of the term Md^2.

I2>I1

hope this helps!!

8 0

3 years ago

Which is an example of a chemical change?

Deffense [45]

Burning a log of wood is an example of a chemical change

5 0

3 years ago

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the

Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height, is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

3 0

3 years ago

Read 2 more answers

A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction

hoa [83]

Given:

Applied stress, $\sigma = 0.45 MPa$

Critical Resolved Stress, $T_{cRss}= 0.242 MPa$

Solution:

a). According to the question, orientation of tensile load is along [1 1 1],

$\sigma = 0.45 MPa$

Now, for resolved shear stress, $\t_{Rss}$ along [1 0 1] within (1 1 T)

let ' $\theta$ ' be the angle between [1 1 1] and [1 0 1], then by coordinate formula:

$cos\theta$ = $\frac{1\times 1 + 1\times 0 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+0^{2}+1^{2}}}}$

$cos\theta$ = $\sqrt{\frac{2}{3}}$

let ' $\phi$ ' be the angle between [1 1 1] and [1 1 1], then by coordinate formula:

$cos\phi = \frac{1\times 1 + 1\times 1 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+1^{2}+1^{2}}}}$

$cos\phi$ = 1

Now, for the resolved components along [1 0 1]

$\t_{Rss}$ = $\sigma cos\theta cos\phi$

$\t_{Rss}$ = $0.45\times 10^{6}\times \sqrt{\frac{2}{3}}\times 1$ = 0.3673 MPa

b). For required tensile stress to produce $T_{cRss}= 0.242 MPa$ :

$\sigma _{1} = \frac{T_{cRss}}{cos\theta cos\phi }$

$\sigma _{1} = \frac{0.242\times 10^{6}}{\sqrt{\frac{2}{3}}\times 1}$

$\sigma _{1} = 0.2964 MPa$

5 0

3 years ago

How much will the top five winners of nasa’s design contest win?

sashaice [31]

Answer:

$\$100,000$

Explanation:

<em>The top 5 winners of NASA's design contest winner received amount of </em> $\$100,000$ <em> </em>(Dollar One hundred thousand)<em>. </em>The respected amount was divided into 5 parts as there were 5 winners as well.

So, the amount was divided among the winners are as follows:

<em>Winner 1 ⇒ </em> $\$20,957.95$

<em>Winner 2 ⇒ </em> $\$20,957.24$

<em>Winner 3 ⇒ </em> $\$20,622.74$

<em>Winner 4 ⇒ </em> $\$19,580.97$

<em>Winner 5 ⇒</em> $\$17,881.10$

Hence by adding all of the 5, we will get the answer, which is $\$100,000$ .

4 0

3 years ago