Answer:
a)V= 0.0827 m³
b)P=181.11 x 10² N/m²
Explanation:
Given that
m = 81.5 kg
Density ,ρ = 985 kg/m³
As we know that
Mass = Volume x Density
81.5 = V x 985
V= 0.0827 m³
The force exerted by weight = m g
F= m g= 81.5 x 10 = 815 N ( Take ,g= 10 m/s²)
Area ,A= 4.5 x 10⁻² m²
The Pressure P
![P=\dfrac{F}{A}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BF%7D%7BA%7D)
![P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B815%7D%7B4.5%5Ctimes%2010%5E%7B-2%7D%7D%5C%20N%2Fm%5E2)
P=181.11 x 10² N/m²
A.) Steel.
steel travels 5,060 meters per second,
lead travels 1,402 meters per second,
water travels 1,439 meters per second,
and air depends on temperature.
Answer:
1.T
2.T
3.T
Explanation:
1.
As we know that bandwidth of the resonance(Δω) and the quality factor(Q) given as
![Q= \dfrac{\Delta \omega_o}{\Delta \omega}](https://tex.z-dn.net/?f=Q%3D%20%5Cdfrac%7B%5CDelta%20%5Comega_o%7D%7B%5CDelta%20%5Comega%7D)
So when quality factor(Q) increases then curve will become narrow.
2.
The impedance of RLC circuit given as
![Z=\sqrt{R^2+(X_c^2-X_L^2)}](https://tex.z-dn.net/?f=Z%3D%5Csqrt%7BR%5E2%2B%28X_c%5E2-X_L%5E2%29%7D)
Where
Xc=Capacitance reactance
XL=Inductance reactance
R=Resistance
At resonance Xc= XL
So
Z= R
3.
As we know that phase angle given as
![tan\phi =\dfrac{X_L-X_C}{R}](https://tex.z-dn.net/?f=tan%5Cphi%20%3D%5Cdfrac%7BX_L-X_C%7D%7BR%7D)
At resonance Xc= XL
![tan\phi =\dfrac{0}{R}](https://tex.z-dn.net/?f=tan%5Cphi%20%3D%5Cdfrac%7B0%7D%7BR%7D)
So Φ = 0°
It means that ,the current and generator voltage are in phase.
So the all statements are true.
Answer:
A sloping surface separating air masses that differ in temperature and moisture content is called a front.