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Serjik [45]
3 years ago
6

A push or pull on an object

Physics
1 answer:
Leno4ka [110]3 years ago
7 0
A pull because you can get the object
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A circuit contains a 305 ohm resistor, a 1.1 micro Farad capacitor, and a 42 mH inductor. At resonance, the impedance is determi
r-ruslan [8.4K]

Answer:

The resistance of the inductor at resonance is 258.76 ohms.

Explanation:

Given;

resistance of the resistor, R = 305 ohm

capacitance of the capacitor, C = 1.1 μF = 1.1 x 10⁻⁶ F

inductance of the inductor, L = 42 mH = 42 x 10⁻³ H = 0.042 H

At resonance the inductive reactance is equal to capacitive reactance.

\omega L = \frac{1}{\omega C}\\\\2\pi F_0 L =  \frac{1}{2\pi F_0 C}\\\\F_0 = \frac{1}{2\pi\sqrt{LC} }

Where;

F₀ is the resonance frequency

F_0 = \frac{1}{2\pi\sqrt{LC} } \\\\F_0 = \frac{1}{2\pi\sqrt{(0.024)(1.1*10^{-6})} }\\\\F_0 =980.4 \ Hz

The inductive reactance is given by;

X_l = 2\pi F_0 L\\\\X_l = 2\pi (980.4)(0.042) \\\\X_l = 258.76 \ ohms

Therefore, the resistance of the inductor at resonance is 258.76 ohms.

5 0
2 years ago
Explanation for x=73km/h•0.5s= 10.14 pls help how did they get 10.14? What was the work around it
Sergio [31]
Hi I am the guy to get mad at
4 0
3 years ago
Any tips on how to get a good grasp of physics and chemistry?
Helga [31]

Answer: Take notes and research into the subject more get extra help like tutoring if needed.

Explanation: ...

4 0
2 years ago
One violin creates a sound whose intensity level is 60dB. Find the intensity level of 16 violins, each playing at this intensity
Yanka [14]

Answer:

72.04 dB.

Explanation:

The intensity level of 60dB corresponds to the sound intensity I given by the equation

60dB = 10log(\dfrac{I}{I_0} )

where I_0 = 1*10^{-12}W/m^2

solving for I we get:

6 = log(\dfrac{I}{I_0} )

10^6 =\dfrac{I}{1*10^{-12}}

\boxed{I = 1*10^{-6} W/m^2}

Now, when 16 violins are playing the intensity I becomes

{I = 16(1*10^{-6} W/m^2)

which on the decibel scale gives

dB = 10log(\dfrac{16*10^{-6}}{1*10^{-12}} )

dB = 72.04\: dB.

Thus, playing 16 violins together gives the intensity level of 72 dB.

8 0
3 years ago
At TTT = 14 ∘C∘C, how long must an open organ pipe be to have a fundamental frequency of 262 HzHz ? The speed of sound in air is
Stolb23 [73]

Answer:

Length of pipe organ(L) = 0647 m (Approx)

Explanation:

Given:

Temperature (T) = 14°C

Fundamental frequency (F) = 262 Hz

Speed of sound (v) = 331 + 0.60(T) m/s

Find:

Length of pipe organ(L)

Computation:

Speed of sound (v) = 331 + 0.60(14) m/s

Speed of sound (v) = 339.4

Length of pipe organ(L) = Speed of sound (v) / 2(Fundamental frequency)

Length of pipe organ(L) = 339.4 / 2 (262)

Length of pipe organ(L) = 0647 m (Approx)

7 0
3 years ago
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