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What are the largest optical telescopes in use today? Why do astronomers want their telescopes to be as large as possible?

Simora [160]

The largest telescope currently used is the Gran Telescopio Canarias, (also known as GTC or GRANTECAN). It is 10.4m in diameter, slightly larger than the Keck telescopes in Hawaii.

The telescope observes the visible and infrared light coming from space and has a primary mirror of 10.4 meters, segmented into 36 hexagonal glass-ceramic pieces, 1.9 m between vertices, 8 cm thick, and 470 kg of mass each. The optical system is completed with two mirrors (secondary and tertiary) that form an image in seven focal stations.

Optically the diameter directly influences the magnification of the image. This added to the fact that astronomical objects are quite far away, a telescope of this magnitude allows to obtain more precise images of what is observed in space

6 0

4 years ago

A particle is confined to a one-dimensional box that is 50 pm long. What is the smallest possible uncertainty in momentum for th

nevsk [136]

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

Momentum= h/4πx

= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

6 0

3 years ago

A golfer hits a ball at an angle of 12 degrees above horizontal. The velocity of the ball is 37 m/s. What is the horizontal dist

ruslelena [56]

72 m is the horizontal distance the travels.

Option: C

Explanation:

The units to express the horizontal and vertical distances are meters (m). The "horizontal" and "vertical" velocities are expressed in "meters per second" (m/s).

Horizontal distance = (initial horizontal velocity)(time)

We can now get the range x from the horizontal component of velocity

$x=v_{x o} \times t$ equation (1)

$\mathrm{v}_{\mathrm{xo}}=\text { initial horizontal velocity }(\mathrm{m} / \mathrm{s})$

x = horizontal distance (m)

t = time (s)

$\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta$

We know that, V = 37 m/s, θ = 12 degree and t = 2 seconds.

To find, $\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times \cos 12$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times 0.974$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=36.038$

$\mathrm{Now}, \mathrm{x}=\mathrm{v}_{\mathrm{xot}}$

$x=36.038 \times 2$

x = 72.076 m ~ 72 m

x = 72 m

The horizontal distance is 72 m.

5 0

4 years ago

If you know the amount of air pressure exerted on a tabletop, how can you calculate the force exerted on the tabletop? Multiply

babymother [125]

Answer:

Multiply the air pressure by the area of the tabletop.

Explanation:

The relationship between pressure, force and area is given by:

$p=\frac{F}{A}$

where in this case, p is the air pressure, F is the force exerted and A the area of the tabletop. By re-arranging the equation, we can solve for F, the force exerted:

$p=\frac{F}{A}\\p\cdot A=\frac{F}{A}\cdot A\\pA=F$

So, the correct answer is:

The force exerted on the tabletop can be found by multiplying the air pressure by the area of the tabletop.

7 0

4 years ago

The tendency of two masses alone in the universe to drift together is a result of

Lynna [10]

Answer:

The answer is gravity

Explanation:

3 0

4 years ago

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