A body staring for rest acquries a velocity of 10ms in 5 seconds calculate (a) the accleration(b) the distance covered by the bo
dy in5 second
1 answer:
Answer:
Acceleration of the body=2m/s square
Distance covered= 25m
Explanation:
Acceleration is found using formula a=v-u divided by t.
Distance covered is found using formula= ut+1 by 2 × at square.
Where initial velocity(u)=0 (body starts from rest)
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