A body staring for rest acquries a velocity of 10ms in 5 seconds calculate (a) the accleration(b) the distance covered by the bo
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Answer:
y = 10.2 m
Explanation:
It is given that,
Charge,
It is placed at a distance of 9 cm at x axis
Charge,
It is placed at a distance of 16 cm at x axis
We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,
Here,
So,
Squaring both sides,
So, at a distance of 10.2 m on the y axis the electric potential equals 0.