Question

A body staring for rest acquries a velocity of 10ms in 5 seconds calculate (a) the accleration(b) the distance covered by the body in5 second

Answer 1

Answer:

Acceleration of the body=2m/s square

Distance covered= 25m

Explanation:

Acceleration is found using formula a=v-u divided by t.

Distance covered is found using formula= ut+1 by 2 × at square.

Where initial velocity(u)=0 (body starts from rest)