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Tasya [4]
3 years ago
8

1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will

the gas occupy?
Chemistry
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

V₂ =  15.00 atm

Explanation:

Given data:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

Final pressure = 760 mmHg ( 760/760 = 1 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ /  P₂

V₂ =  5.00 atm × 3.00 L / 1 atm

V₂ =  15.00 atm

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Answer:

<u>5 moles S x (36.02 g S/mole S) = 180.1 grams of S</u>

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element.  The relationship is known as Avogadro's Number.  This number, 6.02x10^{23} , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than  6.02x10^{23}.  <u>The mole is correlated to the atomic mass of that element.</u>  The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units.  <u>But it can also be read as 36.02 grams/mole.</u>

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<u>This means that 36.02 grams of S contains 1 mole (6.02x</u>10^{23}<u>) of S atoms</u>.

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This relationship holds for all the elements.  Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole.  ^5.38 grams of Zn contains 1 mole of Zn atoms.  

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5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = <u>180.1 grams of S</u>

Note how the units cancel to leaves just grams.  The units are extremely helpful in mole calculations to insure the correct mathematical operation is done.  To find the number of moles in 70 g of S, for example, we would write:

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Answer:

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