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3 years ago

What does the wavelength of a wave measure?

Chemistry

2 answers:

julia-pushkina [17]3 years ago

8 0

Answer:

Explanation:

The wavelength of a wave measure is the width of the wave. It is the amount of distance that is in between two successive crests or troughs of a single wave.

Iteru [2.4K]3 years ago

6 0

Wave length measures the width of the wave

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how many moles of iodine should be added to 750 grams of carbon tetrachloride to prepare a 0.24 m solution

aleksley [76]

Answer:

0.18 mol

Explanation:

Given data

Mass of carbon tetrachloride (solvent): 750 g

Molality of the solution: 0.24 m

Moles of iodine (solute): ?

Step 1: Convert the mass of the solvent to kilograms

We will use the relationship 1 kg = 1,000 g.

$750g \times \frac{1kg}{1,000g} =0.750kg$

Step 2: Calculate the moles of the solute

The molality is equal to the moles of solute divided by the kilograms of solvent. Then,

$m = \frac{moles\ of\ solute }{kilograms\ of\ solvent} \\moles\ of\ solute = m \times kilograms\ of\ solvent = \frac{0.24mol}{kg} \times 0.750kg = 0.18 mol$

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3 years ago

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Mara and ivy are asked to identify two minerals in science class. To do this, they decided to study the physical properties of t

scZoUnD [109]

Answer:

2 only is a pretty accurate answer the others dont make sense to me.

Explanation:

8 0

3 years ago

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What happened during the fusion reaction shown? 2H Зн 4He neutron O A. Two H nuclei fused into one He nucleus. O B. One He nucle

REY [17]

Answer: C.

Explanation:

two H nuclei fused into one He nucleus

3 0

3 years ago

Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO. The following reaction becomes possible: NO3gNOg 2NO2g The

never [62]

There is an error in the first sentence of the question; the right format is:

Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO2.

It should be NO2 and not NO.

Answer:

The equilibrium molarity of NO = 0.21695 m

Explanation:

Given that :

the volume = 500 mL = 0.500 m

number of moles of $NO_3 = 1.9 \ mol$

number of moles of $NO_2 = 1.6 \ mol$

Then we can calculate for their respectively concentrations as :

$[NO_3] = \frac{number \ of \ moles}{volume}$

$[NO_3] = \frac{1.9}{0.500}$

$[NO_3] = 3.8 \ M$

$[NO_2] = \frac{number \ of \ moles}{volume}$

$[NO_2] = \frac{}{} \frac{1.6}{0.500}$

$[NO_2] = 3.2 \ M$

The chemical reaction can be written as:

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

The ICE table is as follows;

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

Initial 3.8 - 3.2

Change +x x -2x

Equilibrium 3.8+x +x 3.2 - 2x

$K_c=\frac{[NO_2]^2}{[NO_3][NO]}$

$where \ K_c = 8.33$

$8.33 = \frac{(3.2-2x)^2}{(3.8+2x)x} \\ \\ 8.33 = \frac{(3.2-2x)^2}{(3.8x+2x^2)}$

$8.33(3.8x + 2x^2) = (3.2-2x)^2 \\ \\ 31.654x + 16.66x^2 = (3.2-2x)(3.2-2x) \\ \\ 31.654x + 16.66x^2 = 10.24 - 12.8x +4x^2 \\ \\ 10.24 - 44.454x -12.66 x^2 = 0 \\ \\ 12.66x^2 +44.454x -10.24 = 0$

Using quadratic formula;

$\frac{-b\pm \sqrt{(b)^2-4ac} }{2a}$

= $\frac{-(44.454) + \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)} \ \ OR \ \ \frac{-(44.454) - \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)}$

= 0.21695 OR -3.7283

Going by the positive value;

x = 0.21695

$[NO_3] = 3.8 +x = 3.8 + 0.21695$

= 4.01695 m

[NO] = x = 0.21695 m

$[NO_2] = 3.2 +x = 3.2 + 0.21695$

= 3.41695 m

3 0

3 years ago

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.300 M , [B] = 1.05 M , and [C] = 0.550 M . The

Hunter-Best [27]

Answer:

Kc = 9.52.

Explanation:

The equilibrium system:

Kc = [C]/[A][B]²,

Concentration: [A] [B] [C]

At start: 0.3 M 1.05 M 0.55 M

At equilibrium: 0.3 - x 1.05 - 2x 0.55 + x

0.14 M 1.05 - 2x 0.71 M

For the concentration of [A]:

∵ 0.3 M - x = 0.14 M.

∴ x = 0.3 M - 0.14 M = 0.16 M.

∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.

∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.

4 0

4 years ago