<h2>Answer:</h2>
<em>Third option is correct, 7.5 grams of CuI.</em>
<h3>Explanation:</h3>
Given data :
Mass of copper = 10 grams
Mass of iodine = 10 grams
theoretical yield of copper iodide = ?
Solution:
Moles of Cu: 10 / 63.5 = 0.157 mol.
Moles of I2: 10 / 254 = 0.039 mol.
Equation : 2Cu + I2 → 2CuI
Limiting reactant : I2
So Moles of CuI produced = 0.039 mol.
Mass of CuI = 0.039 mol * 190.5 = around 7.5g
Answer:
b. erosion.
I believe that this is the best answer
Answer:
B. 400 kPa
Explanation:
the pressure increases, when the temperature increases. and it increases, when the volume decreases.
both cases happen here, each with the factor 2.
so, the pressure increases by the factor 2×2 = 4.
4×100 = 400 kPa
Answer:
the overall cell potential
Explanation:
We must bear in mind that the standard hydrogen electrode is a reference electrode whose electrode potential has been arbitrarily set at 0 V.
The standard hydrogen electrode consists of hydrogen ion solution and hydrogen gas together with a platinum electrode.
The overall cell potential is the reduction potential of the substance being determined using the standard hydrogen electrode as a reference electrode since its electrode potential is set at zero volts.
Answer:
0.535 g
Explanation:
The reaction that takes place is:
- NaCl + AgNO₃ → AgCl + NaNO₃
First we <u>calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- moles = Molarity * liters
<em>Converting 25.0 mL to L </em>⇒ 25.0 / 1000 = 0.025 L
- moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃
Then we <u>convert AgNO₃ moles into NaCl moles</u>:
- 0.00915 mol AgNO₃ *
= 0.00915 mol NaCl
Finally we<u> convert NaCl moles into grams</u>, using its <em>molar mass</em>:
- 0.00915 mol NaCl * 58.44 g/mol = 0.535 g
