Holy I'm not that smart lol but I'll get back to you
Answer: Mechanical energy depends on the motion or position of an object.
Explanation:
Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position).
Answer:
El número atómico de cada uno de los átomos es 26
Explanation:
El número de masa es la suma de las masas del protón y el neutrón de un átomo.
El número atómico es el número de protones en el átomo.
Los parámetros dados son;
La suma del número másico de ambos átomos = 110
La suma de los neutrones = 58
Por lo tanto, sea el número de protones y neutrones en un isótopo = P₁ y N₁ y el número de protones y neutrones en el otro isótopo = P₂ y N₂
Tenemos;
P₁ + N₁ + P₂ + N₂ = 110
N₁ + N₂ = 58
Por lo tanto;
P₁ + P₂ = 110 - (N₁ + N₂)
P₁ + P₂ = 110 - 58 = 52
Dado que los isótopos son del mismo elemento, sus protones serán iguales, por lo tanto;
P₁ = P₂
P₁ + P₂ = P₁ + P₁ = 2 × P₁
P₁ + P₂ = 52
2 × P₁ = 52
P₁ = 52/2 = 26 = P₂
El número atómico de ambos átomos es el número de protones en el átomo que es 26.
El número atómico del elemento del átomo es 26
Answer:
Explanation:
The result will be affected.
The mass of KHP weighed out was used to calculate the moles of KHP weighed out (moles = mass/molar mass).
Not all the sample is actually KHP if the KHP is a little moist, so when mass was used to determine the moles of KHP, a higher number of moles than what is actually present would be obtained (because some of that mass was not KHP but it was assumed to be so. Therefore, there is actually a less present number of moles than the certain number that was thought of.
During the titration, NaOH reacts in a 1:1 ratio with KHP. So it was determined that there was the same number of moles of NaOH was the volume used as there were KHP in the mass that was weighed out. Since there was an overestimation in the moles of KHP, then there also would be an overestimation in the number of moles of NaOH.
Thus, NaOH will appear at a higher concentration than it actually is.