Answer:

Explanation:
Hello,
In this case, the first step is to compute the number of moles of potassium phosphate in 20.0 mL (0.020L) of the 0.015-M (mol/L) solution as shown below:

Thus, these moles correspond to potassium phosphate moles, which molecular formula is K₃PO₄, therefore, one mole of this compound contains three moles of potassium ions as it has three as its subscript in the formula. Thereby, the moles of potassium ions result in:

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Answer:
true
Explanation:
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Q=mcΔT
q=(125g)(0.446 J/(g x °C))(78°C - 23.5°C)
q=(125 g)(0.446 J/(g x °C))(54.5°C) (Be sure to cancel all similar units)
q= 3038.375 J
Answer:more
Explanation:
more or less can help you