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frosja888 [35]
3 years ago
7

How many neutrons are in the element sulfur-34

Chemistry
2 answers:
igomit [66]3 years ago
6 0

Answer:

8 neutrons

Explanation:

Ne4ueva [31]3 years ago
4 0

Answer: neutrons, sulfur-34 would have 18 neutrons and so on.

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skelet666 [1.2K]

Answer:

(ii) 1 dye

(iii) Food coloring F is insoluble in the solvent

(iv) 'E' and 'H'

(b) Food colouring G

Explanation:

Paper chromatography principle is based on the rates of migration of chemicals across a sheet of paper which are different and it consists of a stationary phase such as the water in the paper and a mobile phase such as the solvent resulting in the partitioning of the components of the mixture across the paper

The solution components are positioned to start in one place from where they migrate and separate out on the chromatography paper

(ii) The number of components into which the food colouring 'H' separates into = 1

Therefore, the number of dyes in food colouring 'H' = 1 dye

(iii) Food coloring 'F' does not move because it is insoluble in the solvent, which is the mobile phase

(iv) The food colouring that contains the dye that is likely to be most soluble in the solvent are does for which the dyes travel furthest, which are;

Food coloring 'E' and 'H'

(b) Using a similar question solution found on 'tutor my self' website, we have;

The R_f values are given as follows;

R_f = \dfrac{Distance \ moved \ by \ dye}{Distance \ moved \ by \ solvent}

The distance moved by the solvent = 5 units

The distance moved by dyes in food colouring 'E' and 'H' = 4 units

The distance moved by dye in food colouring 'G' = 3.3 units

The distance moved by the second dye in food colouring 'E' = 2.7 units

By inspection, we get;

R_f dye in food colouring 'G' = 3.3/5 = 0.66,

Therefore, the dye with R_f value closest to 0.67 is the dye in food colouring 'G'.

5 0
3 years ago
Stronitum-90 has a half-life of 29 years. if a site held 2000 kg of this isotope, approximately what mass of strontium-90 would
4vir4ik [10]
A half life of 29 years means that after 29 years, only half of this isotope would be left due to radioactive decay. If we start of with 2000g of it and leave it for 116 years, it would undergo 4 "half=lives". 116/29 = 4. So after the first half life, we would have 2000g/2 = 1000g left. After the second, we would have 500g left, after the third, 250g so after 4 half lives or 116 years, there would be 125 g  of Strontium-90 left at the site.
8 0
2 years ago
Read 2 more answers
____________ rays show areas where large quantities of energy are released.
sladkih [1.3K]

Answer:

Gamma

Explanation:

3 0
1 year ago
Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19​
beks73 [17]

Answer:

E = 3.6×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 550 nm  (550 ×10⁻⁹ nm)

Energy of wave = ?

Solution:

Formula:

E = h c/λ

c = 3×10⁸ m/s

h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm

E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm

E = 0.036×10⁻¹⁷ J

E = 3.6×10⁻¹⁹ J

3 0
2 years ago
How does pollution affect air resources?
tatiyna

Answer: it gets inside the air and then it infects the air's resourses

Explanation:

7 0
3 years ago
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