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Lostsunrise [7]
3 years ago
8

If you burn 22.6 g of hydrogen and produce 202 g of water, how much oxygen reacted

Chemistry
1 answer:
Jlenok [28]3 years ago
8 0
The balanced reaction for the production of water from hydrogen and oxygen is: 2H₂ + O₂→ 2H₂O. Also, the relevant molar masses are the following:

Molar mass of H₂O = 18 g/mol
Molar mass of O₂ = 32 g/mol

We need not be concerned with the amount of hydrogen since we can derive the amount of oxygen that reacted based on the amount of product produced. The following equation is then set-up:

Mass of O₂ reacted = <span>202 g H2O x 1 mol H2O/ 18 g H2O x 1 mol O2/ 2 mol H2O x 32 g O2/ 1 mol O2 = 179.56 g O2

Thus, we have determined that 179.56 g O2 reacted with H2 to produce 202 g of H2O.</span>

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A 10.00 mL sample of vinegar (an aqueous solution of acetic acid) is titrated with 0.5062 M NaOH(aq) and 16.58 mL is required to
sammy [17]

Answer:

5.01%

Explanation:

Density of vinegar = mass/volume

Mass of 10.00 mL = density x volume

                           = 1.006 x 10 = 10.06 g

From the equation of reaction:

CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)

1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.

mole of NaOH = molarity x volume

                      = 0.5062 x 0.01658

                       = 0.008392796‬ mole

0.008392796‬ mole of NaOH will therefore require 0.008392796‬ mole of CH3COOH.

mass of CH3COOH = mole x molar mass

                                     = 0.008392796‬ x 60.052

                                      = 0.504 g

Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%

    = 5.01%

The percent by mass of acetic acid in the vinegar is 5.01%

3 0
2 years ago
When a strip of magnesium metal is placed in an aqueous solution of copper(II) nitrate, elemental copper coats the surface of th
Lera25 [3.4K]

Answer:

1. 2+ (Cu^{2+}).

2. 0 (Cu^0).

Explanation:

Hello,

In this case, the described chemical reaction is a redox reaction in fact, since the oxidation states of both magnesium and copper change as shown due to the displacement:

Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)

Therefore:

1. Since copper is the cation in the copper (II) nitrate, the (II) means that its charge is 2+ (Cu^{2+}).

2. Since copper is alone, it means no electrons are being neither shared not given, its charge is 0 (Cu^0).

Best regards.

4 0
2 years ago
Which of the following oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation
Murljashka [212]

Answer: Option (B) is the correct answer.

Explanation:

When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.

In corn oil, there are no unsaturated sites are present.

In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.

In lard oil, there are around 60% of unsaturated oils.

In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.

Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.

5 0
3 years ago
What sample has particles with the lowest average kinetic energy
makvit [3.9K]

The sample with the lowest AVERAGE kinetic energy is
the coolest one.

The sample with the lowest TOTAL kinetic energy depends on
not only the temperature of the samples, but also on their size,
since each molecule in the sample has kinetic energy.

5 0
2 years ago
If the H3O is 4.950 x 10-12 what is the ph?
romanna [79]

Answer:

pH = 11.3

Explanation:

From the question given above, the following data were obtained:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

The pH of a solution is defined by the following equation:

pH = –Log [H₃O⁺]

Thus, with the above formula, we can obtain the pH of the solution as follow:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

pH = –Log [H₃O⁺]

pH = –Log 4.950×10¯¹²

pH = 11.3

8 0
2 years ago
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