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suter [353]
3 years ago
7

42 At standard pressure, the total amount of heat required to completely vaporize a 100. gram sample of water at its boiling poi

nt is(1) 2.26 X 10 J (3) 2.26 X 103 J
(2) 2.26 X 102 J (4) 2.26 X 105 J
Chemistry
1 answer:
yan [13]3 years ago
4 0

Answer:

4 is the actual answer, the other answer can eat my ...

Explanation:

The answer is 100% legit answer choice 4 not 3!!!!!!

This is because the 2260 is 10^2 and then ^3 is increased when boiling a 100 gram

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Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

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3 years ago
An element consists of two isotopes. One with a mass of 79.95 amu and an abundance of 29.9%. The second isotope has a mass of 81
galina1969 [7]

 the molar  mass of the element  is  81.36 g/mol

<u><em>calculation</em></u>

step 1 : multiply  each %abundance  of the isotope  by   its mass  number

that is 79.95 x 29.9 =2391

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A major disadvantage of a corporation is the
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