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julsineya [31]
4 years ago
6

How can one describe the bond between the two atoms of hydrogen to the one atom of oxygen within a molecule of water (h2o)?

Chemistry
1 answer:
Digiron [165]4 years ago
4 0

There are O-H bonds in H2O. They have the intramolecular force of polar covalent bond.

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What is the freezing point of glucose?
Triss [41]

Answer:

In Fahrenheit it is 294.8°F and in Celsius it is 146°C.

7 0
3 years ago
If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog
9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

8 0
3 years ago
A jar of mixed nuts is a ________ mixture
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It is a heterogeneous mixture <span>
</span>
5 0
3 years ago
Read 2 more answers
Two glucose molecules can combine to form a disaccharide molecule and what molecule
elena-14-01-66 [18.8K]
And a water molecule, this is called a dehydration synthesis. when 2 molecule combine, a water molecule leave.
5 0
3 years ago
How many grams of water can be produced from 4.6 grams of Hydrogen and 7.3 grams of Oxygen?
12345 [234]

Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

Hydrogen = 4 x 1 = 4 g

Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630

From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

                   32 g of O₂ ---------------- 36 g of water

                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

                          x = 8.21 g of H₂O

4 0
4 years ago
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