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laila [671]
3 years ago
9

Predict whether each of the following substances would be more soluble in water (polar solvent) or in a hydrocarbon such as hept

ane (C7H16, nonpolar solvent):
(a) vegetable oil (nonpolar)
(b) isopropyl alcohol (polar)
(c) potassium bromide (ionic)
Chemistry
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

Vegetable oil will dissolve in heptane

Isopropyl alcohol will dissolve in water

Potassium Bromide will dissolve in water

Explanation:

In chemistry, like dissolves like. This implies that polar substances will dissolve in polar solvents and nonpolar substances will dissolve in nonpolar solvents. This is so because, dissolution of a solute in a solvent involves adequate intermolecular interaction between solute and solvent which isn't possible between a polar and a nonpolar substance.

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azamat
<span>The mixture that is most likely to form a suspension is flour and liquid water mixed together, as in a mixture like gravy. A suspension mixture is a mixture that has large solid particles, particles that are large enough for sedimentation.</span>
4 0
3 years ago
2C3H7OH + 9O2 --&gt; 6CO2 + 8H2O
Ne4ueva [31]
<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given]   5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})
  2. Multiply/Divide:                                                                                               \displaystyle 732.767 \ g \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

8 0
3 years ago
What is the relationship between concentration and rate of reaction?
grigory [225]
<h3><u>Answer;</u></h3>

Directly proportional

<h3><u>Explanation;</u></h3>
  • <em><u>Concentration is one of the factors that determine the rate of a reaction. Reaction rates increases with increase in the concentration of the reactants, which means they are directly proportional.</u></em>
  • An increase in the concentration of reactants produces more collisions and thus increasing the rate at which the reaction is taking place. Therefore, <u>Increasing the concentration of a reactant increases the frequency of collisions between reactants and will cause an increase in the rate of reaction.</u>
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Iodine would have chemical properties most like?
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