Answer:
Initial velocity of an object
The acceleration of an object
The change in position of an object
Explanation:
In that equation, you are solving for the final velocity of an object.
Energy at top = m*g*height at top from release point
=0.16*9.81*11.6
=18.21J
At release kinetic energy= Gravtiational energy at top
1/2*0.16*v^2=18.21J
v^2=227.625
v=15.10m/s
Answer:
1.196 m
Explanation:
Given the wave equation :
y= 0.05 cos(5.25x-1775t)
Recall the general traverse wave relation :
y(x, t) = Acos(kx - wt)
A = Amplitude
To Obtian the wavelength ;
We compare the both equations :
Take the value of k ;
kx = 5.25x
k = 5.25
Recall;
k = 2π/λ
5.25 = 2π/λ
5.25λ = 2π
λ = 2π / 5.25
λ = (2 * 3.14) / 5.25 = 1.196 m
Answer: 93ft
Explanation: Martha's eyesight make an angle with the fence, this is solved as a triangle problem.
We first convert all the dimensions to inches using the fact that 12 inches make 1 ft.
To solve for the angle
Tan § = 18/48 = 0.375
§ = tan^-1 of 0.375 = 20.55°
This same angle elevates to the edge of the building
Tan 20.55 = 399/x
x = 399/tan 20.55
x = 1040 inches
Height of building = x + height of fence
Height of building = 1040 + 78 = 1118 inches
Converting back to ft it becomes
1118/12 = 93 ft 2 inches
Approximately 93ft
... We know that there are no forward or backward forces on the object, because its forward speed is constant.
... The left and right forces on the object add up to zero, so it won't begin to move left or right. It'll just keep on with the same 20 m/s forward motion.
... Its velocity after 2 seconds, 10 seconds, or an hour, will still be 20 m/s forward.