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3 years ago

Alternate freezing and thawing often leads to ______.

2 answers:

8 0

Alternate freezing and thawing often leads to :
A. Creep
this occurrence usually occurs when the soils in that specific region is subjected to the temperature below 0 Celcius

hope this helps

WITCHER [35]3 years ago

7 0

The answer from the given options is "A. Creep".

Alternate freezing and thawing often leads to "creep".

Creep refers to the low mass development of soil and soil material down slants, driven fundamentally by gravity yet facilitated by immersion with water and by substitute freezing and thawing. Generally not distinguishable with the exception of through expanded perception.

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A 10- kilogram block is pushed across a horizontal surface with a horizontal force of 20 N against a friction force of 10 N. The

Temka [501]

Answer:

$1m/s^2$

Explanation:

Mass of block=10 kg

Applied horizontal force =F=20 N

Friction force=f=10 N

We have to find the acceleration of block.

Net force=Applied horizontal force-friction force

$ma=F-f$

Where F= Horizontal force

f=Friction force

m=Mass of object

a=Acceleration of object

$10a=20-10=10$

$a=\frac{10}{10}=1 m/s^2$

Hence, the acceleration of the block= $1m/s^2$

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2 years ago

Kayla drew two ray diagrams to compare the behavior of light rays.

Naddika [18.5K]

The answer is the last option

Explanation:

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3 years ago

Read 2 more answers

Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia

Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km west

velocity V1 = 8.9 km/h

distance B = 4.5 km east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7 ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x ) / 8.9 .............2

now equating equation 1 and 2

time A = time B

x / 7 = ( 10.2 - x ) / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

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2 years ago

Which object will be the easiest for a magnet to pull? a 1-gram piece of paper, a 2-gram eraser, a 3-gram steel paper clip, a 4-

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Steel paper clip because it can be moved by the magnet and it is lighter than the iron nail

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2 years ago

the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled p

atroni [7]

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

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2 years ago