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horrorfan [7]
2 years ago
6

Determine whether each described process is endothermic or exothermic.

Chemistry
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

Ice melts into liquid water- endothermic

A process with a calculated positive q - endothermic

Wood burns in a fireplace - exothermic

A process with a calculated negative q - exothermic

Acid and base are mixed, making test tube feel hot - exothermic

Solid dissolves into solution, making ice pack feel cold - endothermic

Explanation:

An endothermic process is one in which heat is absorbed from the surroundings. The absorption of heat means that heat is removed from the surroundings hence the surroundings feel cool. When heat is absorbed, q is positive.

An exothermic process is one in which heat is released to the surroundings. The evolution of heat means that heat is released into the surroundings hence the surroundings feel hot . When heat is evolved, q is negative.

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Which number represents an acidic pH, 4 or 9? _______ Numerical Answers Expected! Answer for Blank 1:
Tasya [4]

Answer:

4

Explanation:

pH scale of acidic is 4.

8 0
3 years ago
What are the molarity and osmolarity of a 1-liter solution that contains half a mole of calcium chloride? How many molecules of
givi [52]

Answer:

Molarity = 0.5 M

Osmolarity = 0.5 x 2 = 1 Osmpl.

Molecules of Cl2 = 6.02 x 10^{23} / 4= 1.505 x 10^{23} no. of molecules

Explanation:

If we add half mole in 1L volume than molarity will obviously be 0.5 M.

The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1

Half will be molecules of Ca and half will be of Cl2 for 0.5M.

6 0
3 years ago
The following information was recorded by a student team working to prepare nickel sulfate. Plan: Prepare NiSO4 by reacting NiO
mixas84 [53]

Answer:

The options e and d are correct.

Explanation:

Mass of NiO = 7.5 g

Moles of NiO = \frac{7.5 g}{74.69 g/mol}=0.10 mol

Moles of sulfuric acid = n

Volume of sulfuric acid ,V= 50 mL = 0.050 L

Molarity of sulfuric acid ,M = 6 mol/L

n=M\time V=6mol/L\times 0.050 L =0.3 mol

NiO + H_2SO_4\rightarrow NiSO_4 + H_2O

According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.

Then 0.10 moles of NiO reacts with :

\frac{1}{1}\times 0.10 mol/=0.10 mol of sulfuric acid.

As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.

According to reaction, 1 mole of NiO gives with 1 mole of NiSO_4.

Then 0.10 moles of NiO wil give :

\frac{1}{1}\times 0.10 mol/=0.10 mol of  NiSO_4.

Molar mass of  NiSO_4 = 154.75 g/mol

Mass of 0.10 moles of NiSO_4:

= 154.75 g/mol × 0.10 mol = 15.475 g

Theoretical mass of NiSO_4 = 15.475 g

Experimental yield of NiSO_4 = 17.4 g

Percentage yield :

\Yield=\frac{\text{Experimental mass}}{\text{Theoretical mass}}\times 100

Percentage yield of NiSO_4:

\Yield=\frac{17.4}{15.475 g}\times 100=112\%

Moles of NiSO_4.6H_2O = 262.85 g/mol × 0.10 mol = 26.285 g

Experimental yield of NiSO_4.6H_2O = 17.4 g

Percentage yield of NiSO_4.6H_2O:

\Yield=\frac{17.4}{26.285 g}\times 100=66.2\%

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