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horrorfan [7]
2 years ago
6

Determine whether each described process is endothermic or exothermic.

Chemistry
1 answer:
FromTheMoon [43]2 years ago
7 0

Answer:

Ice melts into liquid water- endothermic

A process with a calculated positive q - endothermic

Wood burns in a fireplace - exothermic

A process with a calculated negative q - exothermic

Acid and base are mixed, making test tube feel hot - exothermic

Solid dissolves into solution, making ice pack feel cold - endothermic

Explanation:

An endothermic process is one in which heat is absorbed from the surroundings. The absorption of heat means that heat is removed from the surroundings hence the surroundings feel cool. When heat is absorbed, q is positive.

An exothermic process is one in which heat is released to the surroundings. The evolution of heat means that heat is released into the surroundings hence the surroundings feel hot . When heat is evolved, q is negative.

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Answer:

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3 years ago
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Aliun [14]
Cations from smallest to largest
Li⁺ ,Na⁺, K⁺ (from Periodic Table, the bigger number of period, the bigger size, of atom, so the bigger size of cation)

1) LiF smaller  cation then KF
1,036                                 <span>853
</span><span>The lattice energy increases as cations get smaller, as shown by LiF and KF.
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7 0
3 years ago
Read 2 more answers
A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of w
Oksanka [162]

Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

M=58g

Explanation:

From the question we are told that:

Heat Capacity H=0.897

Mass of water M=200g

Initial Temperature of Aluminium T_a=85.6

Initial Temperature of Water T_{w1}=16.0

Final Temperature of Water  T_{w2}=16.0

Generally

Heat loss=Heat Gain

Therefore

M*0.897*(85.6-20.1) =200*4.184*(20.1-16)

M=58g

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