The activity coefficient of h is 0.05
The ph of the solution is 2.08
To find the activity coefficient, apply the concept of ionic equilibrium
h( activity coefficient)= 1/2CZ²
C is the concentration of species
Z is the charge on individual species
<em>h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)</em>
<em>h= 0.05 </em>
For the pH of the solution, apply the formula
<em>pH= -log( H⁺x0.83)</em>
<em>pH = - log(0.01x0.83)</em>
<em>= 2.08</em>
To learn more about the pH of the solution, visit brainly.com/question/26767292
#SPJ4
Answer:
Explanation:
Hello there!
In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:
Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
Best regards!
Answer:
Mass = 121 g
Explanation:
Given data:
Mass in gram of CO₂ = ?
Volume = 61.8 L
Pressure = standard = 1 atm
Temperature = 273.15 K
Solution:
Formula:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 61.8 L = n ×0.0821 atm.L/ mol.K × 273.15 k
61.8 L.atm = 22.42 atm.L/ mol × n
n = 61.8 L.atm /22.42 atm.L/ mol
n = 2.76 mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 2.76 mol × 44 g/mol
Mass = 121 g
