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2 years ago

How does a sound wave differ from an electromagnetic wave

2 answers:

8 0

A sound wave is very low frequency as it starts off on the Wave spectrum, You can tell if the frequency is low or high by the wavelength.

the wavelength is how wide the wave is from crest to crest (crest: the top of the wave)

If the wavelength is very long, it means that there is low frequency, the closer the crests are the higher frequency there is throughout the wave!

So sound waves are much less frequent or concentrated, than Electromagnetic waves.

If you don't understand this, go look at some pictures of the wave spectrum. It should help a bit!

http://hyperphysics.phy-astr.gsu.edu/hbase/ems1.html

vladimir1956 [14]2 years ago

7 0

A sound wave is a mechanical wave and cannot travel through empty space. It needs to travel through a medium of some kind. To remember this, the saying "no one can hear you scream in space" is somewhat helpful considering sound waves cannot travel through an empty vacuum like such. An electromagnetic wave ( EM wave ) does not need a medium to travel and can travel freely through empty space.

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Assume that a lightning bolt can be modeled as a long, straight line of current. If 16 C of charge passes by a point in 1.50 x 1

Reptile [31]

Answer:

$B = 7.9012*10^{-5}T$

Explanation:

To solve the problem, the concepts related to the magnetic field and the current produced in a lightning bolt are necessary.

The current is defined by the load due to time, that is to say

$I= \frac{q}{t}$

Where,

$q= Charge$

$t = time$

So the current can be expressed as:

$I = \frac{16}{1.5*10^{-3}}$

$I = 10666.67A$

Once the current is found it is now possible to find the magnetic field, as this is given by the equation,

$B =\frac{\mu_0}{2\pi}\frac{I}{r}$

Where,

$\mu_0 =$ Permeability Constant

I= Current

r= radius

Replacing the values we have

$B=\frac{4\pi*10^{-7}}{2\pi}(\frac{10666.67}{27})$

$B = 7.9012*10^{-5}T$

7 0

2 years ago

Tonya is thinking about the topic presented in the text, "Do opposites really attract?" Which of her thoughts is an example of c

tigry1 [53]

tanya is dumb j j j j j j j j j jj j j j

6 0

3 years ago

In 1-2 sentences describe how your nose cleans the air you inhale.

svp [43]

Answer: Your nose inhales O2 and goes through these little nose hairs to keep stuff that doesn't belong in your airway, it goes through your nose into your lungs taking in O2 for your blood. The other substances that you have inhaled get absorbed elsewhere and it is converted into CO2 which is what you exhale.

Explanation:

3 0

3 years ago

A 60 W lightbulb is on for 24 hours. A stereo with a power of 150 W is on for 2

Helen [10]

Answer:

B) The lightbulb uses 4,104,000 J more than the stereo.

6 0

2 years ago

A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$

$\theta = tan^{-1} (\frac{d}{\mu L})$

Replacing,

$\theta = tan^{-1} (\frac{0.9}{0.42*2})$

$\theta = 46.975\°$

Therefore the minimum angle that the person can reach is 46.9°

8 0

2 years ago