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3 years ago

HELP ME 20 POINTS!!!Assume that the average volume of an adult human body is one-tenth

Physics

2 answers:

Agata [3.3K]3 years ago

8 0

Answer:

,Assume that the average volume of an adult human body is one-tenth

cubic meter (0.10 m) and that there are two billion (2.0 x 109)

adults in the world.

a. What would be the total volume of all the adults in the world?

b. Compute the length of one edge of a cubic container that has a

volume equal to the volume of all the adults in the world.

MrRissso [65]3 years ago

3 0

a). (2.0 x 10^9) x (0.1) = 2.0 x 10^8 cubic meters

b). The edge of a cube with that volume is

(2.0 x 10^8) ^ 1/3 = about 585 metres

(about 0.36 of a mile)

==> I'm pretty sure there are actually more than 2 billion adults in the world, since the total population is well over 7 billion now.

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4 years ago

What happens to the distance between interference fringes if the separation between two slits is increased?

kolezko [41]

Answer:

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Explanation:

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3 years ago

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ikadub [295]

Answer:

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3 years ago

The guy wires AB and AC are attached to the top of the transmission tower. The tension in cable AB is 9.1 kN. Determine the requ

Oksana_A [137]

Answer:

T_ac = 6.586 KN

R = 10.51 KN

Explanation:

Given:

- Tension in cable T_ab = 9.1 KN

Find:

- Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A

- Determine the magnitude R of this downward force.

Solution:

- Compute the three angles as shown in figure attached, a, B , y:

a = arctan (40/50) = 38.36 degrees

B = arctan (50/30) = 59.04 degrees

y = 180 - 38.36 = 82.6 degrees

- Use cosine rule to calculate R and F_ac as follows:

sin(a) / T_ac = sin(B) / T_ab = sin(y) / R

sin(38.36) / T_ac = sin(59.04) / 9.1 = sin(82.06) / R

T_ac = 9.1 * ( sin(38.36) / sin(59.04) )

T_ac = 6.586 KN

R = 9.1 * ( sin(82.06) / sin(59.04) )

R = 10.51 KN

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3 years ago

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valentina_108 [34]

Answer:

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2 years ago