Answer:
44100 N
Explanation:
Each wall will have dimension of 4 m x 1.5 m
Whole force will act on central point of wall situated at a depth of 1.5 /2 = .75m
pressure at CM = h d g , h = .75 , d ( density of water = 10³ )
pressure at CM = .75 x 10³ x 9.8
= 7350 N / m²
Total force on each wall
= pressure x area
= 7350 x 4 x 1.5
= 44100 N Ans
b ) If h = 1.5 x 2 = 3
Pressure = hdg
1.5 x 10³ x 9.8
= 14700 N / m²
Force
= pressure x area
14700 x 3 x 4
= 176400 N
Which is 4 times 44100 N
So force will quadruple.
It is so because both area and height have become twice.
F=ma
50=100a
a=50/100
a=0.5 m/s^2
Average speed = (distance covered) / (time to cover the distance)
Average speed = (14 km) / (249 min)
Average speed = (14/249) (km/min)
Average speed = (14/249) (km/min) x (60 min/hr)
Average speed = (14 x 60 / 249) km/hr
<em>Average speed = 3.37 km/hr</em>
The average amount of solar energy incident on the PV per day is 10000 kWh/day.
<h3>
Equation</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Let the PV array has an area equal to 50 square meters. Hence:
Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.
Find out more on Equation at: brainly.com/question/2972832
Answer:
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