This can be solve using heat
balance. The amount of heat the lead released is equal to the amount of heat
the ice absorb.
The heat release by the leas = m1*Cp*deltaT
Where m1 is the mass of lead
Cp is the specific heat of lead
Delta is the change of temperature
Heat absorbed by the ice = m2Lf
Where m2 is the mass of ice
Lf is the latent heat of fusion of
ice
M1*Cp*deltaT = m2Lf
(15g) ( 0.128 j/g C) ( 120 -0 C) =
m2(333/g)
Solving for m2
<span>M2 = 0.69 kg of ice melts</span>
Answer:
The sound intensity that the other student measure, I₂ is expected to be;
A) 6.2 × 10⁻⁸ W/m²
Explanation:
The measure of sound intensity is given by the following formula;


Where;
I = The intensity
R = The radius
P = The power of the sound
Whereby we have;
The distance of the two people talking, R₁ = 3.0 m
The measure of the sound intensity, I₁ = 1.1 × 10⁻⁷ W/m² (from an online source)
The distance of the other student from the two people talking, R₂ = 4.0 m
Therefore, the estimate of the sound intensity, I₂, is given as follows;


I₂ = 6.1875 × 10⁻⁸ W/m²
∴ The sound intensity that the other student measure, I₂ ≈ 6.2 × 10⁻⁸ W/m²
Mandatory friction makes it difficult for a free body of mass to move with constant speed.
Amethyst... because it's silicon dioxide
Answer:
B. A object in motion stays in motion, and an object at rest stays at rest unless acted upon by a net force.