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Tems11 [23]
3 years ago
5

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what's the acceleration of the object

? A. 33 m/s B. 5.42 m/s C. 2.75 m/s D. 13.58 m/s
Physics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

C. 2.75

Explanation:

acceleration = (v2 - v1) /t

(98 - 65) / 12 =2.75

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Marina86 [1]

Answer:

F=-88Ib

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)

F=u*N

with \mu =0.47

F=98.7Ib

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

F=-88Ib

5 0
3 years ago
What happens to its kinetic energy when its reaches the maximum height ?​
drek231 [11]

when it reaches the maximum height, all the energy has now been converted into potential energy.when a ball is thrown straight upto into the air,all its initial kinetic energy converted into gravitational potential energy when it reaches its maximum height

7 0
3 years ago
Find the intensity in decibels [i(db)] for each value of i. normal conversation: i = 106i0 i(db) = power saw a 3 feet: i = 1011i
White raven [17]

Answer:

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i(dB)=110

Jet engine at 100 feet: i=1018i0

i(dB)=180

Explanation:

if these are the same as edge, then these are the answers! :)

8 0
3 years ago
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A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
ira [324]
According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/s^{2}.
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F = 6 kg * 2.3 m/s^{2} = 13.8 N
Hope this helps!
6 0
3 years ago
A pendulum is hanging from a tower. The pendulum almost touches the ground and has a period of 18.0 s. What is the height of the
nadya68 [22]
We apply the following equation

T = 2π * sqrt (L/g)

Where g is the gravity = 9.8 m/s^2

L is the longitude of the pendulum (Height of the tower)

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We find L.............> (T /2π)^2 = L/g

L = g*(T /2π)^2...........> L = 80.428 meters
5 0
3 years ago
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