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zloy xaker [14]
3 years ago
15

What is 3×300 and show work

Mathematics
2 answers:
just olya [345]3 years ago
6 0
3 times 0 is zero and 3 times 3 is 9 quite simple :)

garri49 [273]3 years ago
3 0
3*300=900

300
3
____
900
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5n(3n+8) ..? I don't understand
SSSSS [86.1K]
You have ti distribute the 5n into the brackets. 

so then youll have 15n^2 + 40n. 
5 0
3 years ago
Hello, just need the answer for this question. Thank you for your help if you do so.
musickatia [10]

Answer:

In the first one you are missing (x - 3) so it will be 4(x - 3) and if you factor it out it will be 4x - 12

In the second one you are missing a (x -5)which means 9x(x -5) or when you factor it out it will be 9x^2 - 45x

Step-by-step explanation:

3x^2 -23x + 40 = (3x - 8) (x - 5)

3x^2 -17x + 24 = (3x -8) ( x - 3)

7 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Every one reading this please help! I don't understand this and I will give brainliest to the person that helps first with a goo
stira [4]
Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.

The length of the poster in its frame is ...
  (frame width on one side) + (poster length) + (frame width on the other side)
  2 in + 32 in + 2 in = 36 in

Likewise, the width of the poster in its frame is ...
  2 in + 24 in + 2 in = 28 in

The area of a rectangle 36 in by 28 in is the product of these dimensions:
  Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
6 0
3 years ago
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a truck can be rented from company a for $90 a day plus $0.40 per mile. company b charges $50 a day plus $0.80 per mile to rent
Neporo4naja [7]
101 miles.
truck A $130.4
truck B $130.8
7 0
3 years ago
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