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3 years ago

What is 3×300 and show work

Mathematics

2 answers:

just olya [345]3 years ago

6 0

3 times 0 is zero and 3 times 3 is 9 quite simple :)

garri49 [273]3 years ago

3 0

3*300=900

300
3
____
900

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Write a real world problem that could be solved by using the equation <img src="https://tex.z-dn.net/?f=3x-25%3D125" id="TexForm

forsale [732]

Answer:

x=50

See below for word problem.

Step-by-step explanation:

While shopping, you spend $125 before tax. You buy 3 dresses at the same price each and receive a $25 discount. How much is the price of each dress?

3x-25=125

3x=125+25

3x=150

x=50

8 0

4 years ago

2-1/2 cups water minus 1-2/3 cups water =

weeeeeb [17]

The difference between the mixed numbers is equal to 5/6.

<h3>How to perform the subtraction between the two mixed numbers?</h3>

A mixed number is a number that is written as a whole number plus an improper fraction, here we want to compute:

(2 + 1/2) - (1 + 2/3)

We can group the whole numbers and the fractions, so we get:

(2 - 1) + (1/2 - 2/3)

Now we can simplify this so we get:

(2 - 1) + (1/2 - 2/3)

= 1 + (3/6 - 4/6) = 1 - 1/6 = 6/6 - 1/6 = 5/6

We conclude that the difference between the mixed numbers is equal to 5/6.

If you want to learn more about mixed numbers:

brainly.com/question/1746829

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7 0

2 years ago

Calculate the middle number between 1-5 and 7.1

prohojiy [21]

Answer:

-4

Step-by-step explanation:

1-5=-4 (7.1+1)-5=3.1

6 0

3 years ago

Read 2 more answers

A man buys a jacket birr 300 before VAT what is the VAT and the total cost?

Novosadov [1.4K]

Base price=300
Let VAT be x%

Now

Total VAT=0.x(300)

Total cost:-

300+300(0.x)

7 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago