Answer:
what is that supposed to even mean
Explanation:
Answer:
12 m/s
Explanation:
Using the continuity equation, which is an extension of the conservation of mass law
ρ₁A₁v₁ = ρ₂A₂v₂
where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.
ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow
A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)
A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)
v₁ = velocity of the fluid flowing at point 1 = 3 m/s
v₂ = velocity of the fluid flowing at The restriction = ?
ρ₁A₁v₁ = ρ₂A₂v₂
Becomes
A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)
(πD₁²/4) × 3 = (πD₂²/4) × v₂
3D₁² = D₂² × v₂
But
D₂ = (D₁/2)
And D₂² = (D₁²/4)
3D₁² = D₂² × v₂
3D₁² = (D₁²/4) × v₂
(D₁²/4) × v₂ = 3D₁²
v₂ = 4×3 = 12 m/s
Answer:
percentage by volume of the solute = 45%
Explanation:
The percentage by volume of the solute in a solution is the percentage of the volume of the solute as against the overall volume of the solution.
In this example,
volume of solution = 300mL
volume of solute = 135mL
% volume of solute = (volume of solute ÷ volume of solution) × 100
= (135 ÷ 300) × 100
= 0.45 × 100 = 45%
∴ percentage by volume of the solute = 45%
Explanation:
Use the height of the cliff to determine how long it took the car to land.
Take down to be positive. Given:
Δy = 7.93 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
7.93 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.27 s
Use the time to calculate the horizontal velocity.
Given:
Δx = 26.7 m
a = 0 m/s²
Find: v₀
Δx = v₀ t + ½ at²
26.7 m = v₀ (1.27 s) + ½ (0 m/s²) (1.27 s)²
v₀ = 21.0 m/s
The driver was going 21.0 m/s, faster than the speed limit of 9.72 m/s.
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