A jetliner has a velocity of 95 m/s. What is the displacement of the jetliner at t=3.0 seconds?
1 answer:
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Answer:
A.
B.s=397.6 m
Explanation:
Given that
speed u= 284.4 m/s
time t = 1.4 s
here he want to reduce the velocity from 284.4 m/s to 0 m/s.
So the final speed v= 0 m/s
We know that
v= u + at
So now by putting the values
0 = 284.4 -a x 1.4 (here we take negative sign because this is the case of de acceleration)
So the acceleration while stopping will be .
Lets take distance travel before come top rest is s
We know that
s=397.6 m
So the distance travel while stopping is 397.6 m.