The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
1/2
Step-by-step explanation:
The dog has 12 for 1 meal.
12=1
6 is half of 12.
6=1/2
Answer:
The iron weighed 1/12 pound more than the aluminum.
Step-by-step explanation:
The weight of the aluminum is given as 1/2 pound. But that can also be written as 6/12 pound.
This is a subtraction problem (subtracting fractions...so also a common denominator problem)
In order to subtract fractions you have to get a common denominator.
7/12 - 1/2
= 7/12 - 6/12
= 1/12
The iron is 1/12 pound heavier than the aluminum.
True because you are actually quadrant 1 is all positives
