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creativ13 [48]
3 years ago
6

What is the slope of the line represented by the equation y + 3 = -4(X-5)?

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

y-5=-3(x-17)

y-5=-3x+51  

y=-3x+46

compare with equation

y=mx+c

slope = -3

Step-by-step explanation:

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Xin graphs the equation y =4x - 6.
Art [367]

Answer:

Both D and E are true statements.

Step-by-step explanation:

When you have the base form of slope-intercept form:

y = mx + b

The m (which is the coefficient of x) is the slope of the line. In this case that would be 4.

The b is the intercept. In this case it would be -6

8 0
3 years ago
Simply using exponents .Then find the products .
aksik [14]

Answer:

\sqrt[7]{b^{15}}

Step-by-step explanation:

=> b^2*\sqrt[7]{b}

=> b^2*b^{1/7}

Where bases are same, powers are to be added.

=> b^{2+(1/7)}

=> b^ {14+1/7}

=> b^{15/7}

=> \sqrt[7]{b^{15}}

6 0
3 years ago
An honest die is rolled. If the roll comes out even (2, 4, or 6), you will win $1; if the roll comes out odd (1,3, or 5), you wi
jenyasd209 [6]

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable <em>X</em> denotes the number of heads in <em>n</em> tosses of an honest coin (<em>n</em> ≥ 30), then <em>X</em> has an approximately normal distribution with mean, \mu=\frac{n}{2} and standard deviation, \sigma=\frac{\sqrt{n}}{2}.

Here the number of tosses is, <em>n</em> = 2500.

Since <em>n</em> is too large, i.e. <em>n</em> = 2500 > 30, the random variable <em>X</em> follows a normal distribution.

The mean and standard deviation are:

\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, <em>μ</em> = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

        = μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

        = 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

                                   = 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

7 0
3 years ago
At Glencliff High School, the photography
olga_2 [115]

Answer:

23+12=

Step-by-step explanation:

you just need figure it out in your head and see what sounds right

4 0
3 years ago
Read 2 more answers
Lucy si thinking of a Numbers. The number is greater than two hundred twenty-five. Her number is less than 2 hundreds,2 tens, an
VikaD [51]
226 i believe, if not then idk
8 0
3 years ago
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