Answer:
131.8 g.
Explanation:
- There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):
<u><em>d = m / V.</em></u>
d = 0.8787 g/ml.
V = 0.15 L x 1000 = 150 ml.
- ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
Answer:
14 mol e⁻
Explanation:
Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese
8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)
Step 2: Calculate the moles corresponding to 110 g of manganese
The molar mass of Mn is 55 g/mol.
110 g × 1 mol/55 g = 2 mol
Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn
According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.
2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻
