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3 years ago

Which pair of elements would form an ionic bond? n and o k and be c and cl fe and ni

Chemistry

1 answer:

Grace [21]3 years ago

4 0

Answer:

k and be

Explanation:

because ionic bond occurs between a metal and a non metal

I would appreciate if my answer is chosen as a brainliest answer

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Na2S+2AgNO3 = Ag2S + NaNO3 If 2.86g of Ag2S are actually produced by a reaction between an excess of Na2S and 4.27g of AgNO3 the

Advocard [28]

Answer:

D. 91.0%

Explanation:

Hello,

In this case, for the given chemical reaction:

$Na_2S+2AgNO_3 \rightarrow Ag_2S + 2NaNO_3$

Next, since silver nitrate (molar mass 169.87 g/mol) is in a 2:1 molar ratio with silver sulfide (molar mass 247.8 g/mol), we compute its theoretical yield as shown below:

$m_{Ag_2S}^{theoretical}=4.27gAgNO_3*\frac{1molAgNO_3}{169.87gAgNO_3} *\frac{1molAg_2S}{2molAgNO_3}*\frac{247.8gAg_2S}{1molAg_2S}\\\\m_{Ag_2S}^{theoretical}=3.11gAg_2S$

Next, we compute the percent yield as:

$Y=\frac{m_{Ag_2S}^{actual}}{m_{Ag_2S}^{theoretical}}*100\% =\frac{2.86g}{3.11g} *100\%\\\\Y=91.0%$

Hence, answer is D. 91.0%.

Best regards.

7 0

4 years ago

Explain each of these impacts and suggest a solution that would reduce the losses caused by bycatch.

Dennis_Churaev [7]

Answer:

Bycatch can negatively affect species such as dolphins, sea turtles, protected fish, and whales by harming animals, contributing to population declines, and impeding population recovery. Other impacts of fisheries on marine mammals may include removal of their preferred prey and sometimes habitat damage.

Explanation: hey could i get to kno u or sum

6 0

3 years ago

The actions described in the passage are best understood in the context of which of the following?

soldi70 [24.7K]

C
I have had this question on a test before!! Hope this helps

6 0

4 years ago

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in

GaryK [48]

Answer is: 25.84 milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0

4 years ago

If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

Darina [25.2K]

The question is incomplete, here is the complete question:

A bottle of rubbing alcohol having aqueous solution of alcohol contains 70% (v/v) alcohol. If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

<u>Answer:</u> The amount of water present in the given bottle of rubbing alcohol is 283.8 mL

<u>Explanation:</u>

We are given:

Volume of bottle of rubbing alcohol = 946 mL

70% (v/v) alcohol solution

This means that 70 mL of rubbing alcohol is present in 100 mL of solution

Amount of water present in solution = [100 - 70] = 30 mL

Applying unitary method:

In 100 mL of solution, the amount of water present is 30 mL

So, in 946 mL of solution, the amount of water present will be = $\frac{30}{100}\times 946=283.8mL$

Hence, the amount of water present in the given bottle of rubbing alcohol is 283.8 mL

4 0

3 years ago