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jok3333 [9.3K]
2 years ago
6

Which pair of elements would form an ionic bond? n and o k and be c and cl fe and ni

Chemistry
1 answer:
Grace [21]2 years ago
4 0

Answer:

k and be

Explanation:

because ionic bond occurs between a metal and a non metal

I would appreciate if my answer is chosen as a brainliest answer

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The number with a lower value is the number of protons and the number with a higher value is the mass
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What is the change of state from solid to gas called?
maxonik [38]

Your answer is C. Sublimation :)(

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2 years ago
What is pOH of water?<br><br> A. 10^7<br><br> B. 10^-7<br><br> C. 7 <br><br> D. -7
Olenka [21]

Answer:

C. 7 is the pH scale of water.

7 0
3 years ago
The aromatic hydrocarbon cymene (C10H14) is found in nearly 100 spices and fragrances, including coriander, anise, and thyme. Th
andrezito [222]

Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

Explanation :

First we have to calculate the heat released by the combustion.

q=c\times \Delta T

where,

q = heat released = ?

c = specific heat of calorimeter = 3.640kJ/^oC

\Delta T = change in temperature = 19.35^oC

Now put all the given values in the above formula, we get:

q=3.640kJ/^oC\times (19.35)^oC

q=70.43kJ

Thus, the heat released by the combustion = 70.43 kJ

Now we have to calculate the molar enthalpy combustion.

\Delta H=-\frac{q}{n}

where,

\Delta H = molar enthalpy combustion = ?

q = heat released = 70.43 kJ

n = number of moles cymene = \frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole

\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole

Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

4 0
3 years ago
The value of Kp for the reaction 2 A(g) + B(g) + 3 C(g) → 2 D(g) + E(g) is 18530 at a particular temperature. What would be the
Lady bird [3.3K]

Answer:

Kp2=5.3967x10^{-5}

Explanation:

Hello there!

In this case, since the Kp for the first reaction is given, according to the following equilibrium expression:

Kp=\frac{p_D^2p_E}{p_A^2p_Bp_C^3} =18530

However, since the second reaction stands for the reverse of the initial one, the equilibrium expression would be:

Kp_2=Kp=\frac{p_A^2p_Bp_C^3}{p_D^2p_E}

And therefore its Kp the inverse of the aforementioned one:

Kp2=1/18530\\\\Kp2=5.3967x10^{-5}

Best regards!

5 0
3 years ago
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