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yaroslaw [1]
3 years ago
10

What portion of your salt solution in ice water system is: a. A mixture? b. A solution?

Chemistry
1 answer:
ahrayia [7]3 years ago
8 0

The salt and water are a homogeneous mixture but when salt dissolves in the water system is called a solution of salt and water.

<h3>What is a mixture? </h3>

A mixture is defined as the combination of two or more substances that are not chemically bonded together.

There are two types of mixture which include:

  • Homogeneous (uniform composition) and

  • Heterogeneous mixtures

When salt is added to the ice water system, it lowers the freezing point of the ice water thereby forming a homogenous mixture of water and salt.

The dissolution of salt in ice water leads to the formation of salt and water solution.

Learn more about mixture here:

brainly.com/question/10677519

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What is 1.0 x 10^4 L in nL?
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Answer:

= 10000000000000 Nanoliters

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1.0 x (10^4) L =

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0.65 moles of O2 originally at 85°C is cooled
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Answer:

2.09 atm

Explanation:

We can solve this problem by using the equation of state for an ideal gas, which relates the pressure, the volume and the temperature of an ideal gas:

pV=nRT

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V is its volume

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R is the gas constant

T is the absolute temperature

In this problem we have:

n = 0.65 mol is the number of moles of the gas

V = 8.0 L is the final volume of the gas

T=40C+273=313 K is the temperature of the gas

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Heart, 5 stars, and Brainiest to first right answer!
erastovalidia [21]

hi have a nice day

will be less than 26 °C as water has a relatively higher specific heat than sand.

Explanation:

The specific heat of a substance is the amount of heat energy absorbed by one unit of mass of the substance when its temperature increases one unit.

From that, you can derive the equation for the specific heat of a substance:

specific heat = heat / (mass × ΔT)

Thus, assuming that all the heat provided by the lamp to both samples is the same and, as given, the amount (mass) of both samples is also the same, you have that the specific heat of the samples will be:

specific heat = constant / ΔT

So, specific heat and ΔT are inversely related.

It is known that water has a higher specific heat than sand (that is why the sand on the shore of a beach is, during the day, hotter than the water and your feet get burned when you walk on a sandy beach on a sunny day

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