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solmaris [256]
3 years ago
10

Water flows at low speed through a circular tube with inside diameter of 2 in. A smoothly contoured body of 1.5 in. diameter is

held in the end of the tube where the water discharges to atmosphere. Neglect frictional effects and assume uniform velocity profiles at each section. Determine (a) the pressure measured by the gage and (b) the force required to hold the body.

Engineering
1 answer:
Art [367]3 years ago
5 0

Answer:

Pressure = 11.38 psi

Force = 13.981 Ibf

Explanation:

Step by step solution is in the attached document.

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1. How many board feet in piece of Oak that is 1" thick 6" wide and 8' long?
enyata [817]

Answer:

  4

Explanation:

A "board foot" is 1/12 of a cubic foot. It is the volume of a board 1" thick and 1 foot square.

Here, the board is 1" thick, so the number of board feet is numerically equal to the number of square feet of area it has.

  (1/2 ft)(8 ft) = 4 ft²

The number of board feet is 4.

7 0
4 years ago
1 import java.util.Scanner; 3 public class EqualityAndRelational { 4 public static void main (String args) args) { int userBonus
Anastaziya [24]

Missing Part of the Question

Complete the expression so that userPoints is assigned with 0 if userBonus is greater than 20 (second branch). Otherwise, userPoints is assigned with 10 (first branch

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

( Your solution goes here)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

Answer;

Replace

( Your solution goes here)

With

if(userBonus>20).

The full program becomes

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

if(userBonus>20)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

7 0
4 years ago
Explain why you should never stand directly in line with the engine fan when the engine is running.​
Snowcat [4.5K]

Answer:it is dangerous to stand behind a running engine. running engine of a vehicle produces carbon monoxide which is dangerous for us

Explanation:

3 0
3 years ago
Steam enters an adiabatic nozzle at 2.5 MPa and 450oC with a velocity of 55 m/s and exits at 1 MPa and 390 m/s. If the nozzle ha
luda_lava [24]

Answer:

The value of exit temperature from the nozzle = 719.02 K

Explanation:

Temperature at inlet T_{1} = 450°c = 723 K

Velocity at inlet V_{1} = 55 \frac{m}{sec}

velocity at outlet V_{2} = 390 \frac{m}{sec}

Specific heat at constant pressure for steam  C_{p}  = 18723 \frac{J}{kg k}

Apply steady flow energy equation for the nozzle

h_{1} + \frac{V_{1} ^{2} }{2} = h_{2} + \frac{V_{2} ^{2} }{2}

C_{p} T_{1}  + \frac{V_{1} ^{2} }{2} = C_{p} T_{2} + \frac{V_{2} ^{2} }{2}

Put all the values in the above formula we get,

⇒ 18723 × 723 + \frac{55^{2} }{2} = C_{p} T_{2} + \frac{390^{2} }{2}

⇒   T_{2} = 719.02 K

This is the value of exit temperature from the nozzle.

4 0
4 years ago
Show the ERD with relational notation with crowfoot. Your ERD must show PK, FKs, min and max cardinality, and correct line types
zhenek [66]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

3 0
4 years ago
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