Answer:
-209 kJ
Explanation:
I did the math. You're welcome ;)
Answer:
The number ratio is 4:7
Explanation:
Step 1: Data given
Compound 1 has 50.48 % oxygen
Compound 2 has 36.81 % oxygen
Molar mass oxygen = 16 g/mol
Molar mass manganese = 54.94 g/mol
Step 2: Calculate % manganes
Compound 1: 100 - 50.48 = 49.52 %
Compound 2: 100 - 36.81 = 63.19 %
Step 3: Calculate mass
Suppose mass of compounds = 100 grams
Compound 1:
50.48 % O = 50.48 grams
49.52 % Mn = 49.52 grams
Compound 2:
36.81 % O = 36.81 grams
63.19 % Mn = 63.19 grams
Step 4: Calculate moles
Compound 1
Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles
Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles
Compound 2
Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles
Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles
Step 5: calculate mol ratio
We will divide by the smallest amount of moles
Compound 1
O: 3.155/0.9013 = 3.5
Mn: 0.9013 / 0.9013 = 1
Mn2O7
Compound 2
O: 2.301 / 1.150 = 2
Mn: 1.150 / 1.150 = 1
MnO2
The number ratio is 2:3.5 or 4:7
Answer:
The maximum kinetic energy of electron is = 2.93 × 
Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × 
J s
c = speed of light = 3 × 
= 261 nm = 261 × 
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron = 
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule
Answer:
Explanation:
Half reaction:
(1)
balance: 
(2)H and O balance in acidic medium:
(3) charge balance:
Hence balanced half-reaction:
