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Advocard [28]
3 years ago
7

Which cell has the better survival plan, animal or plant cell? Support your answer with facts I WILL GIVE BRAINLIEST ANSWER

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
7 0
If im not mistaken plant cells go through a stage called photosynthesis meaning the cells can create it's own energy (food) off of water, Co2 and sunlight.
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pH indicator. A dye that is an acid and that appears as different colors in its protonated and deprotonated forms can be used as
Vitek1552 [10]

Answer:

pH = 7.8

Explanation:

The Henderson-Hasselbalch equation may be used to solve the problem:

pH = pKa + log([A⁻] / [HA])

The solution of concentration 0.001 M is a formal concentration, which means that it is the sum of the concentrations of the different forms of the acid. In order to find the concentration of the deprotonated form, the following equation is used:

[HA] + [A⁻] = 0.001 M

[A⁻] = 0.001 M - 0.0002 M = 0.0008 M

The values can then be substituted into the Henderson-Hasselbalch equation:

pH = 7.2 + log(0.0008M/0.0002M) = 7.8

7 0
3 years ago
When water is released from a dam, what happens?
malfutka [58]

Answer:

Potential energy is transformed to kinetic energy

Explanation:

Once a river is dammed it changes its physical and chemical structure. Damming also changes the biological communities associated with the river and its floodplain. When water is kept behind dams, seasonal flow patterns are usually lost.

A hydroelectric dam converts the potential energy stored in a water reservoir behind a dam to mechanical energy—mechanical energy is also known as kinetic energy. As the water flows down through the dam its kinetic energy is used to turn a turbine.

5 0
2 years ago
There are 13 instances on the periodic table where the atomic mass does not increase along with atomic number. For each of these
Aneli [31]

Answer:

i don't know the answer right now

8 0
3 years ago
What is the molarity of a solution that contains 0.702 mol KCl in 0.98 L solution?
Lubov Fominskaja [6]

Answer:

C. 0.72 M

Explanation:

To calculate the molarity use the following equation, C=n/V

You have the molar number n which is 0.702 and the volume 0.98 L

Replace those numbers in the formula C=0.702/0.98= 0.72 M

6 0
2 years ago
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin
Studentka2010 [4]

Answer : The initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

1.2\times 10^{-4}=k(0.40)^a(0.40)^b(0.40)^c ....(1)

Expression for rate law for second observation:

3.6\times 10^{-4}=k(0.40)^a(0.40)^b(1.20)^c ....(2)

Expression for rate law for third observation:

4.8\times 10^{-4}=k(0.80)^a(0.40)^b(0.40)^c ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-4}=k(0.80)^a(0.80)^b(0.40)^c ....(4)

Dividing 1 from 2, we get:

\frac{3.6\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(1.20)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{4.8\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{4.8\times 10^{-4}}{4.8\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.80)^a(0.80)^b(0.40)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

1.2\times 10^{-4}=k(0.40)^2(0.40)^0(0.40)^1

k=1.875\times 10^{-3}M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 0.55 M of reagent A and 0.80 M of reagents B and C.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(1.875\times 10^{-3})\times (0.55)^2(0.80)^0(0.80)^1

\text{Rate}=3.63\times 10^{-4}Ms^{-1}

Therefore, the initial rate for a reaction will be 3.63\times 10^{-4}Ms^{-1}

4 0
3 years ago
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