A. Use average bond energies together with the standard enthalpy of formation of C(g) (718.4 kJ/mol ) to estimate the standard e
nthalpy of formation of gaseous benzene, C6H6(g). (Remember that average bond energies apply to the gas phase only.)
B. Compare the value you obtain using average bond energies to the actual standard enthalpy of formation of gaseous benzene, 82.9 kJ/mol. What does the difference between these two values tell you about the stability of benzene?
B. Compare the value you obtain using average bond energies to the actual standard enthalpy of formation of gaseous benzene, 82.9 kJ/mol. What does the difference between these two values tell you about the stability of benzene?
1 answer:
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Explanation:
A chemical equilibrium is defined as the state of reaction in which the rate of forward reaction is equal to the rate of backward reaction.
When Q > , then it means that the reaction is proceeding in the backward reaction. Whereas if Q <
, then it means that the reaction is proceeding in the forward direction. Hence, formation of products will be favored.
On the other hand, if Q = , then it means reaction is at equilibrium.
At equilibrium, it is not necessary that the concentrations of products divided by the concentrations of reactants equals one.
Thus, we can conclude that the statement for a chemical system at equilibrium, the forward and reverse rates of reaction are equal, is correct.