Answer:
Ethanoic or acetic acid.
Explanation:
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In this case, since the chemical formula of the compound excludes the hydrogen from the CHO form, we can infer it is a leaving group, which is likely to be bonded with an oxygen due to the high polarity of the O-H bond. In such a way, the most feasible condensed structure is:
Whereas the COOH stands for the carboxyl group; therefore the compound is ethanoic acid or acetic acid.
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Answer:
-8024.832 J
Explanation:
The amount of heat energy lost or released, Q, can be calculated thus;
Q = m × c × ∆T
Where;
Q = amount of heat lost (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to this question,
Q = ?
m = 24.3 g
c of Gold = 0.129 J/g°C
∆T = 20°C - 2580.0°C = -2560°C
Using Q = m × c × ∆T
Q = 24.3 × 0.129 × -2560°C
Q = -8024.832 J
This means that 8024.832 J of energy is lost or released.
Answer:
The maximum amount of work that can be done by this system is -2.71 kJ/mol
Explanation:
Maximum amount of work denoted change in gibbs free energy during the reaction.
Equilibrium concentration of B = 0.357 M
So equilibrium concentration of A = (1-0.357) M = 0.643 M
So equilibrium constant at 253 K,
[A] and [B] represent equilibrium concentrations
When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M
So reaction quotient at this situation,
We know,
where R is gas constant and T is temperature in kelvin
Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and is 0.555
So,
= -2710 J/mol
= -2.71 kJ/mol
Answer:
NOPE
Explanation:
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