Elements 3 to 10 (Li to Ne) show a more or less steady increase in IE. What does this tell you about the energy level that each
1 answer:
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Answer : The atomic radius for Ti is,
Explanation :
Atomic weight = 47.87 g/mole
Avogadro's number
First we have to calculate the volume of HCP crystal structure.
Formula used :
.............(1)
where,
= density =
Z = number of atom in unit cell (for HCP = 6)
M = atomic mass = 47.87 g/mole
= Avogadro's number
V = volume of HCP crystal structure = ?
Now put all the values in above formula (1), we get
Now we have to calculate the atomic radius for Ti.
Formula used :
Given:
c/a ratio = 1.669 that means, c = 1.669 a
Now put (c = 1.669 a) and (a = 2R) in this formula, we get:
Now put all the given values in this formula, we get:
Therefore, the atomic radius for Ti is,