Answer: There are 6.9 mol of
are required to react completely with 2.30 mol of S.
Explanation:
The given reaction equation is as follows.

Here, 1 mole of S is reaction with 3 moles of
which means 1 mole of S requires 3 moles of
.
Therefore, moles of
required to react completely with 2.30 moles S are calculated as follows.

Thus, we can conclude that there are 6.9 mol of
are required to react completely with 2.30 mol of S.
Answer:
3.72 mol Hg
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Density = Mass over Volume
Explanation:
<u>Step 1: Define</u>
D = 13.6 g/mL
54.8 mL Hg
<u>Step 2: Identify Conversions</u>
Molar Mass of Hg - 200.59 g/mol
<u>Step 3: Find</u>
13.6 g/mL = x g / 54.8 mL
x = 745.28 g Hg
<u>Step 4: Convert</u>
<u />
= 3.71544 mol Hg
<u>Step 5: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.71544 mol Hg ≈ 3.72 mol Hg
Answer:
yes the one that is circled is correct
Explanation: