Question

Two tiny particles carrying like charges of the same magnitude are apart. if the electric force on one of them is what is the magnitude of the charge on each of these particles?(k = 1/4πε0 = 9.0 × 109 n • m2/c2)

Answer 1

Answer:

$2.4\times 10^{-8} C$

Explanation:

We are given that

Distance between two tiny particles=d=1mm=$1\times 10^{-3} m$

Force,F=5 N

We have to find the magnitude of the charge on each of these particles.

Let charge on each particle=q

By Coulomb's law of force

$F=\frac{kq_1q_2}{r^2}=\frac{kq^2}{r^2}$

Where $k=9\times 10^9$

Substitute the values

$5=\frac{9\times 10^9q^2}{(1\times 10^{-3})^2}$

$q^2=\frac{5\times (1\times 10^{-3})^2}{9\times 10^9}$

$q=\sqrt{\frac{5\times (1\times 10^{-3})^2}{9\times 10^9}}$

$q=2.4\times 10^{-8} C$