Answer:
6.32 × 10⁻³
3.2560008× 10⁷
5.630× 10⁰
9.5002× 10¹
Explanation:
Scientific notation is the way to express the large value in short form.
The number in scientific notation have two parts.
The digits (decimal point will place after first digit)
× 10 ( the power which put the decimal point where it should be)
For example:
0.00632
In scientific notation = 6.32 × 10⁻³
32,560,008
In scientific notation = 3.2560008× 10⁷
5.630
In scientific notation = 5.630× 10⁰
95.002
In scientific notation = 9.5002× 10¹
The alloy has a density of 21.186g/cc. So for a kilogram or 1000 grams/21.186 g/cc= 45.7 cc. So the answer is 45.7 cc of the allow to make up a kilogram which shows that the density of the allow can be used to calculate the volume of a larger mass ie the kilogram.
<span>1.
London forces. 4. dipole - dipole. Due to a small hydrogen atom and a
much large fluorine atom, with a large , positive nuclus and large,
negative, p orbitals . This makes it very polar.</span>
Answer:
18.
Explanation:
1) according to the reaction (M(Fe)=56; M(O₂)=32; V₀=22.4):
4Fe+3O₂⇒2Fe₂O₃; - ν(O₂)=0.75*ν(Fe);
2) ν(Fe)=m(Fe)/M(Fe)=60/56≈1.071 [mol];
3) ν(O₂)=0.75*1.071=0.804 [mol];
4) V(O₂)=V₀*ν(O₂); ⇒ V(O₂)=22.4*0.804=18 [lit].
We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:
PV=nRT
We manipulate this equation to give us an expression which will correspond to density. We do as follows:
PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L
